The acceleration of a particle is inversely proportional to the square of the time since it was fired.If the acceleration of the particle 15 seconds after it was fired was 5 m/sec2, what was its acceleration 10 seconds later?
1. The acceleration of a particle is inversely proportional to the square of the time since it was fired.If the acceleration of the particle 15 seconds after it was fired was 5 m/sec2, what was its acceleration 10 seconds later?
Jawaban:
3,3m/sec²
Penjelasan:
maybe ¯\_(ツ)_/¯ᵐᵃʸᵇᵉ
2. A man jogged for 2 km with a constant speed. He accelerated his journey at 09.15 to reach 5 m/s in 10 seconds. What is his acceleration?
Jawaban:
what
Penjelasan:
semoga bermanfaat
3. A car starts from rest and rolls down a hill with constant acceleration. It travels a distance of 500 m in 20 sec. Calculate its acceleration.
A car starts from rest and rolls down a hill with a constant acceleration. It covers a distance of 500 m in 20 seconds. So the acceleration is 1,25 m/s²
Discussion
Is known :
distance (s) = 500 m
time (t) = 20 second
Asked :
acceleration (a)?
Answered :
Find the speed first
v = s/t
v = 500/20
v = 25 m/s
Find acceleration
a = v/t
a = 25/20
a = 1,25 m/s²
Conclusion
So, the acceleration is 1,25 m/s²
Answer Details
Subjects : Mathematics
Category : Measurement time, angle, distance, and speed
Categorization code : 5.2.2
keyword : acceleration
4. a ball in a straight line slows down from 8m/s to 2m/s in 10 seconds, what is the acceleration?
diket : vo = 8 m/s
vt = 2 m/s
t = 10 s
dit : a = ...?
Jawab
a = delta v/ delta t
= vt - vo / t
= 2 - 8 / 10
= -6 / 10
= - 0,6
yang artinya (-) berarti diperlambat
maaf klo salah
5. Example: The velocity of a particle moving along the x axis varies in time according to the expression vx = (40 - 5t2) m/s, where t is in seconds. a. Find the average acceleration in the time interval t = 0 to t = 2.0 s b. Determine the acceleration at t = 2.0 s. Example: The velocity of a particle moving along the x axis varies in time according to the expression vx = (40 - 5t2) m / s, where t is in seconds. a. Find the average acceleration in the time interval t = 0 to t = 2.0 s b. Determine the acceleration at t = 2.0 s.
Jawaban:
a. - 10 m/s²
b. - 20 m/s²
Penjelasan:
Vx = (40 - 5t²)
a.
saat t₁ = 0 --> Vx₁ = 40 m/s
saat t₂ = 2 --> Vx₂ = 40 - 5. 4 = 20 m/s
Average acceleration
ar = ΔV/Δt = ( Vx₂ - Vx₁ ) / ( t₂ - t₁ )
ar = ( 20 - 40 )/( 2 - 0 )
ar = - 10 m/s² ( perlambatan )
b.
acceleration at t = 2.0 s.
a = dV/dt = - 10. t
a = - 10. 2 = - 20 m/s²
6. A mass of car 1750 kg starts from rest and moves along straight road with a constant acceleration, reaching a speed of 20 m/s after 5 second. The resultant force acting on the car during the first 5 seconds is..... 1750 N a.
Jawaban:
The resultant force acting on the car during the first 5 seconds can be calculated using the equation for force, which is Force = Mass x Acceleration.
The acceleration of the car can be calculated using the equation for acceleration, which is Acceleration = Change in velocity / Time.
Change in velocity = Final velocity - Initial velocity = 20 m/s - 0 m/s = 20 m/s
Time = 5 seconds
So, acceleration = 20 m/s / 5 seconds = 4 m/s^2
Force = Mass x Acceleration = 1750 kg x 4 m/s^2 = 7000 N.
Therefore, the resultant force acting on the car during the first 5 seconds is 7000 N.
Penjelasan:
7. A minibus moves with initial velocity of 10 m/s. After 5 seconds, its velocity changes to 20 m/s. Calculate its average acceleration.-TIA
-GLBB-
Diketahui:
Vo = 10 m/s
Vt = 20 m/s
t = 5 s
Ditanya:
a =__?
Jawab:
a = (Vt - Vo) / t
a = (20 - 10) / 5
a = 10 / 5
a = 2 m/s²
8. dari gambar ini yang bener "motion can be described by algebraic equation if it has constant acceleration" atau "Velocity and acceleration can be described by algebraic equation if it has constant acceleration" ? subjeknya mana yang tepat? it disini refers to apa?
jawabannya "Velocity and acceleration can be described by algebraic equation if it has constant acceleration"
"it" refers to "velocity and acceleration"
sekian.....
9. A particle moves for 10 s with velocity 4 m/s and then moves with velocity 6 m/s for another 20 s and finally moves with velocity 8 m/s for next 30 s. What is the average velocity of the particle?
Jawaban:
average v= v1 + v2 + v3
3
= (10×4) + (20x6) + (8 x 30)
3
= 40 + 120 + 240
3
= 400 = 133.33 m/s
3
10. The rate constant for a first-order reaction is 3.64. 10 - 2 seconds -1 at 298 k.. what is the rate constant for the reaction at 350 k if the activation energy of the reaction is 50.2 kj/mol. given: the quantity r = 8.314 j/k.mol.
Jawaban terlampir di foto ya!
#GeniuzS05
#SAYIDI
11. A particle moves to the right along the x-axis. After t second, the particle position at X1 = 3 meters and after moving 4 seconds, the particle position at x2 = 12 meters. What is the average speed of the moving particles?
Jawaban:
3 m/s
Penjelasan:
S=12
t=4
v=S/t
v= 12/4
v=3 m/s
12. which best describes the motion of the object recorded in data belowa. it doesnt moveb. it maintains a constant velocity.c. it undergoes positive acceleration.d. it undergoes negative acceleration.tolong di jawab yaaa
Jawaban:
B. It maintains a constant velocity.
Penjelasan:
Constant speed is a straight-line motion, where the acceleration can change but the speed is constant.
semoga membantu^^
13. Translate Wash them often with soap for at least 20 seconds
Jawaban:
Sering-seringlah mencucinya dengan sabun setidaknya selama 20 detik.
Penjelasan:
semoga membantu
14. A car sets off from traffic lights. It reaches a speed of 27 m/s in 18 seconds. What is its acceleration?
vo = 0
vt = 27 m/s
t = 18 s
vt = vo + at
27 = 0 + a(18)
a = 27/18 = 1.5 m/s^2
15. derive the formula for work done by a constant force
Work is done when a force is applied, at least partially, in the direction of the displacement of the object. If that force is constant then the work done by the force is the dot product of the force with the displacement: W = F ⃗ ∙ d ⃗ .
16. 15. Lita : How long should we wash our hands withsoap, Lisa?Lisa :A. We should wash them for at least 20 seconds.B. We would wash them for at least 20 minutes.C. We would wash them for at least 20 seconds.D. We should wash them for at least 20 minutes.
Jawaban:
c. we would wasd them for at least 20 seconds
Maaf klau slah
17. 5x + (k + 1)y = -207x - 2ky = 2y + 6are simultaneous equations, where k is a constant.(a) Solve the equations for x and y, giving your answer for y in terms of the constant k.
Jawaban:
x=-2 dan
[tex]y = \frac{ - 10}{k + 1} [/tex]
Penjelasan dengan langkah-langkah:
langkah-langkah ada di lampirannya ya, semoga membantu
18. A particle P is moving in a horizontal circle about O. It moves at constant speed V. Which statement is true?
Jawaban:
There are several statements that could be true regarding a particle P moving in a horizontal circle about point O at constant speed V, but some possibilities include:
The centripetal acceleration of the particle P is given by a = V^2 / r, where r is the radius of the circle.
The direction of the centripetal force acting on the particle P is towards point O.
The particle P has a velocity vector that is tangential to the circle at every point along its path.
The angular velocity of the particle P, which is the rate at which it sweeps out angle as it moves around the circle, is given by ω = V / r.
Without additional information, it is not possible to determine which of these statements, or others, might be true.
Penjelasan:
19. A particle moves along the x axis according to the equation x = 2.00 + 3.00t - 1.00t2, where x is in meters and t is in seconds. At t = 3.00 s, find a. the position of the particle, b. its velocity, c. its acceleration.
Jawabnya pake bahasa indonesia aja ya...
a. x = posisi ( meter ) , t = waktu ( sekon ) = 3.00 sekon
x = 2.00 + 3.00t - [tex]1.00 t^{2} [/tex] = 2 + 3t - [tex] t^{2} [/tex]
= 2 + 3(3) - [tex] 3^{2} [/tex] = 2 + 9 - 9 = 2 meter
b. v = [tex] \frac{x}{t} [/tex] = [tex] \frac{2}{3} [/tex] = 0,66 m/s
c. Karena posisi awalnya 0 dan belum ada gerakan, maka percepatan sama
dengan kecepatan = 0,66 m/s
Mohon maaf bila keliru
20. A car is moving with an initial velocity of 20 m/s and then moving with constant acceleration of 4 m/s? The velocity of a car after 20 seconds is ... O a. 120 m/s O b. 150 m/s O C. 80 m/s O d. 100 m/s
Jawaban:
given : v1 = 20 m/s
a = 4 m/s^2
t = 20 s
ask :v2 .... ?
answer :
a = (v2 - v1)/ tv2 = at + v1 = 4×20 + 20 = 100 m/sGood luck....
Jawaban:
d. 100m/s
Penjelasan:
know
Vo=20m/s
a=4m/s²
t=20s
asked
vt=?
solution
The velocity of a car after 20 seconds:
vt=Vo+at
vt=20+4(20)
vt=20+80
vt=100m/s
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