Suneeta Moves A Distance Of 9 Meters

Mike and John are standing in front of a plane mirror at a distance of 6 meters and 2 meters respectively. What is the distance of Mike's image as seen by John? (maap kalo pertanyaan nya dalam bahasa inggris)

Daftar Isi

1. Mike and John are standing in front of a plane mirror at a distance of 6 meters and 2 meters respectively. What is the distance of Mike's image as seen by John? (maap kalo pertanyaan nya dalam bahasa inggris)

The distance of Mike's image as seen by John is 8 m

Solution

Plane mirror reflects the angle of reflection as same as the angel of incidence, so the distance of object will be the same with distance of image.

Look at the attached figure:

the distance of Mike's image as seen by John is denoted d, based on the picture and plane mirror reflection the value of d is;

d=6+2

d= 8 m

Learn more about optic

1.Lens https://brainly.co.id/tugas/15628623

2.Microscope https://brainly.co.id/tugas/10634650

3.Mirror https://brainly.co.id/tugas/10577664

4.Optical Instruments https://brainly.co.id/tugas/20736021

5.Optic https://brainly.co.id/tugas/8790382

Answer Detail

Grade: 11

Subject: Physics

Chapter: Chapter 11 - Optical Instruments

Code: 11.6.11

Keywords: Lens, mirror, reflection

2. 3.A car moves with constant velocity of 30km/hour. The distance traveled after 5minutes is...

Jawaban:

2.5 km

Penjelasan:

Speed = 30 km/hour

= 30 km/60 minutes

= 0.5 km/minutes

Distance after travel 5 minutes =

0.5 x 5 = 2.5 km

3. 2 poin32. The distance on a map using 1:700 scale of two places is 8 cm. Howmany meters is in the actual distance? *

Jawaban:

scale 1:700.

distance 8 cm

700x8 = 5600 cm = 56 m

Penjelasan dengan langkah-langkah:

semoga bermanfaat

4. A rectangle has a perimeter of 42 meters and a length of 13 meters. Find the width of the rectangle.

The width of the rectangle is 8 meters.

[tex]\\[/tex]

Pembahasan

(Explanation)

The formula of the perimeter of a rectangle is p =length + width + length + width.It can be simplified to p =2(length + width) or p = 2(l + w). As we know the length of the rectangle and the formula of the perimeter of a rectangle, we can use the formula to find the width of the rectangle as follows.

⇒ p = 2(l + w)

⇒ 42 = 2(13 + w)

⇒ 42 = 2(13) + 2(w)

⇒ 42 = 26 + 2w

⇒ -2w = 26 - 42

⇒ -2w = -16

⇒ w = -16/-2

⇒ w = 8

Therefore, the width of the rectangle is 8 meters.

[tex]\\[/tex]

Pelajari Lebih Lanjut

(Learn More)

5. An aircraft was at an altitude of 3,000 meters above sea surface. A dolpin was 200 meters below sea surface. If the aircarf went down as far as 100 meters toward sea surface, how many meters was the distance between the aircraft and dolphin ?

300 metres, because the aircraft was 100 metres toward sea surface and the dolphin was 200 metres below sea surface.

6. How many meters distance if do you meet others?

1-3 meters
hope it helps
semangat bljrny

Jawaban:

1 meter is rarely recommended

#social_distancing

7. A particle moves to the right along the x-axis. After t second, the particle position at X1 = 3 meters and after moving 4 seconds, the particle position at x2 = 12 meters. What is the average speed of the moving particles?

Jawaban:

3 m/s

Penjelasan:

S=12

t=4

v=S/t

v= 12/4

v=3 m/s

8. Find the approximate distance that will be saved by walking diagonally across a field 450 meters by 250 meters instead of walking along the two adjacent sides.

Jawaban:

distance that will be saved = 700 - 160 √10

Penjelasan dengan langkah-langkah:

distance diagonally=

[tex]c =\sqrt{ {a}^{2}+}b^{2}\\c=\sqrt{45{0}^{2}+{250}^{2}}\\c = \sqrt{202500 +62500 } \\ c = \sqrt{265000} \\ c = 160\sqrt{10} [/tex]

dustance by walking two adjacent=

250 +450= 700m

distance that will be saved = 700 - 160 √10

9. Ahmad pushes an object with a horizontal force of 150 N and it moves as far as 5 meters, the work done is

Diketahui :

F = 150 N

s = 5 meter

Ditanyakan :

Usaha/Work ( w) = ...?

Jawab :

Hubungan antara jarak suatu objek ketika didorong dengan suatu gaya dengan gaya adalah :

w = F . s

Sehingga :

w = F . s

= 150 . 5

= 750 N

Mata Pelajaran : Fisika

Materi : Usaha dan Eenergi

Kelas : 10 SMA

10. If a cyclist in the Tour de France traveled southwest a distance of 12,250 meters in one hour, what would the velocity of the cyclist be?

Jawaban:

Kita tahu bahwa kecepatan diartikan sebagai laju jarak yang ditempuh per satuan waktu, jarak / waktu, serta memiliki kecepatan dan arah. Di sini, kita diberi tahu bahwa dalam waktu satu jam, pengendara sepeda menempuh jarak 12.250 meter. Jadi, kami tahu bahwa:

t = 1 jam

d = 12.250 m

Kita juga tahu bahwa ada 60 detik dalam satu menit dan 60 menit dalam satu jam, dan kita mungkin menginginkan kecepatan dalam satuan meter per detik, m / s. Jadi, mari gunakan persamaan yang relevan dan masukkan angka dan konversi unit kita:

v = d / t

= 12.250 m * 1 jam * 1 menit

1 jam 60 menit 60 detik

= 3.403 m / s barat daya

Jika Anda perlu melaporkan arah dalam satuan derajat atau radian, buat timur 0 ° atau 0 radian, dan putar 45 ° atau π / 4 radian 5 kali berlawanan arah jarum jam untuk mendapatkan 225 ° atau 5π / 4 radian.

11. The distance between ken’s house and his school is 5.5 km. what is the distance in meters?

Jawab:5500 meters

Penjelasan dengan langkah-langkah: cause km to meters take 3 stairs down

if it goes down it's multiplied and if it goes up it is divided

I'm sorry I don't really speak English well

12. Two particles A and B are initially separated at a distance of 1200 m each other. Particle A moves with velocity of 10 m/s and particle B moves with velocity of 5 m/s. When and where do both of them meet it they move approaching each other and depart at the same time?

Jawaban:

ini b.inggris loh kok fisika

13. A body starting from rest moves with constant acceleration. what is the ratio of distance covered by the body during the fifth second of time to that covered in the first 5.00 s?

Jawaban:

kak nga tau bahasa inggris

Distance covered in nth second =

S(n) =(a/2)(2n-1),therefore

S(5)=9a/2

Distance covered in time t=

S=ut+1/2at^2, since u=0, we get,

S=25a/2

S(5):S=(9a/2)/(25a/2)=9:25

14. 5.Length of the Suramadu's bridge is ...a. 5.400 metersb. 192 metersc.494 metersd. 526 meters

Jawaban:

Length of the Suramadu's Bridge is 5.438meters

Jawaban:

A. 5.400 maaf klo salah

lebih tepatnya 5.438 meters

15. Raj drove 1/9 of 72 km and hiked the rest of the distance. What was the distance Raj hiked?

Jawaban:

raj kihed jawaban nya 89 km

16. We measure distance in ______. A. kilometers (km) B. kilograms (kg) C. millimeters (mm) D. meters (m)

Jawaban:

We measure distance in ______.

*A. Kilometers (km).

Pembahasan:

Kami mengukur jarak dalam ______.

A. Kilometer (km)✅

B. Kilogram (kg).

C. Milimeter (mm).

D. Meter (m).

Penjelasan:

The unit of length is a unit used to describe the size of the height, length, distance of an object or object being measured. In the length of the ladder there are units of length kilometers (km), hectares (hm), decameters (dams), meters (m), decimeters (dm), centimeters (cm), millimeters (mm). Each step up one rung is divided by 10 and every step down one rung is multiplied by 10.

Semoga membantu:-)

Jangan lupa jawabannya dikasih terbaik><

17. Which of the following would produce the most power? A. A mass of 2 kilograms lifted 10 meters in 10 seconds B. A mass of 5 kilograms lifted 5 meters in 10 seconds C. A mass of 1 kilograms lifted 10 meters in 5 seconds D. A mass of 2 kilograms lifted 10 meters in 5 seconds

Jawaban:

b.a mass of 5 kilograms lifted 5 meters in 10 seconds

Penjelasan:

maaf kalo salah

Answer:

Explanation:

Formula for power: P = W/Δt

Formula for work: W = N.s = m.a.s

Formula for force: F = m.a

Formula for acceleration: a = [tex]\frac{vt-v0}{t}[/tex]

vt = final velocity

v0 = starting velocity

t = time

(edit)

since the questions state how high the item travels in a set period of time, here's how to calculate the speed and acceleration!

for example:

I'll use block A.

Block A traveled 10 meters in 10 seconds, so the speed would be 10 meters divided by 10 seconds, which equates to 1 m/s.

The acceleration would be 1 m/s, which is the final velocity, minus 0, which is the starting velocity, divided by 10 seconds, which is the amount of time required to travel the set distance. So, following the formula, the equation would be a = [tex]\frac{1 - 0}{10 s}[/tex], which equals [tex]\frac{1}{10}[/tex]m/s², or 0.1 m/s².

Using those numbers, we can calculate the amount of force produced, which is F = m.a. Plugging the numbers in, it would be F = 2 kg. 0.1 m/s², which equals 0.2 N.

From here, we just need to calculate the work using W = m.a.s, which calculates to W = 0,2N . 10 m= 2 J, and calculate the amount of power it would generate using P = W/Δt, which calculates to P = 2 J / 10 s, which is the amount of time required to travel the set distance. After all that, we get the equation P = 2 J / 10 s, which equals to 0.2 Watts.

A: Power = F.s/Δt = (2 kg . 1 m²/s²) / 10 s = 0.2 W

B: Power = F.s/Δt = (5 kg . 0.5 m²/s²) / 10 s = 0.25 W

C: Power = F.s/Δt = (1 kg . 2 m²/s²) / 5 s = 0.4 W

D: Power = F.s/Δt = (2 kg . 2 m²/s²) / 5s = 0.8 W

Hence, D would produce the most power.

I'm sorry for the lots of edits. I just felt like there's some explaining to do there!

18. 0 Date: what is the dept of linting lake? the has a dept of a.over 100 meters b.lesthan 100 meters c.100 meters d.over 100 meters

Jawaban:

loh harusnya belajar bahasa indo bu

kan Negara lain penghianat

19. A van moves with velocity of 36 km/hour. then it is accelerated with acceleration of 2 m/s². calculate : a) velocity, b) distance traveied in 10 second after the van being accelerated

a) s = 25 m = 0,025 km , t = 5 s = 5/3600 jam , v = 36 km/jam

b) s = 200 m = 0,2 km , t = 10 s = 10/3600 jam , v = 30 m/s^2 = 108 KM/jam

20. If a rectangle has a perimeter of 28 meters and a width of 5 meters, find the length of the rectangle.

The length of the rectangle is 9 meters.

[tex]\\[/tex]

Pembahasan

(Explanation)

To find the length of the rectangle, we first need to know the formula of the perimeter of a rectangle, which is:

p = l + w + l + w or p = 2(l + w)

where:

l = length w = width

Since we know that the width of the rectangle is 5 meters and the formula of the perimeter of a rectangle is 2(l + w), we can find the length of the rectangle by using the formula as follows.

⇒ p = 2(l + w)

⇒ 28 = 2(l + 5)

⇒ 28 = 2(l) + 2(5)

⇒ 28 = 2l + 10

⇒ -2l = -28 + 10

⇒ -2l = -18

⇒ l = -18/-2

⇒ l = 9

Hence the length of the rectangle is 9 meters.

[tex]\\[/tex]

Pelajari Lebih Lanjut

(Learn More)

Wawasan Genius