A bullet of mass 0.20 kg travels horizontally at a speed of 400 m/s. it strikes a stationary wooden block of mass 1.80 kg resting on a frictionless, horizontal surface. the bullet stays in the block. what is the speed of the bullet and the block immediately after the impact? 200 m/s 80 m/s 44 m/s 40 m/s (in ulanganku hari ini)
1. A bullet of mass 0.20 kg travels horizontally at a speed of 400 m/s. it strikes a stationary wooden block of mass 1.80 kg resting on a frictionless, horizontal surface. the bullet stays in the block. what is the speed of the bullet and the block immediately after the impact? 200 m/s 80 m/s 44 m/s 40 m/s (in ulanganku hari ini)
Jawaban:
40 m/s
Penjelasan:
Known :
Mb = 0.20 kg
Vb = 400 m/s
Mw = 1.8 kg
Vw = 0 m/s (Resting)
Solution :
Because bullet stays in the block, then the speed of the bullet and the block will be same :
Mb . Vb + Mw . Vw = (Mb + Mw) . V
0.2 . 400 + 0 = (0.2 + 1.8) . V
V = 40 m/s
2. The total mass of a block of butter and a box of cherries is 384 g. The mass of theblock of butter is twice the mass of the box of cherries. Find the mass of the blockof butter.
draw model: ∆∆∆
384÷ 3 = 128
cherries = 128 g
butter = 2x 128
butter = 256 g_____
semangat belajar....
3. Mass of a banana is 0.1 kg. Given a formula to calculate weight, w = m x g, where w is weight, m is mass, and g is strength of gravity. Calculate weight of a banana on Earth. [strength of gravity on Earth 10 N/kg] *
Penjelasan:
mass= 0.1 kg
gravity = 10 N/kg
weight = mass×gravity
= 0.1×10 = 1
4. A mass of 2 kg rotates at constant speed in a horizontal circle of radius 5 m and the time forone complete revolution is 3 s. The force acting on the mass is
Jawaban:
40phi^2 /9
Penjelasan dengan langkah-langkah:
Dik: m=2 kg
r=5 m
t=3 s
Dit: Fs=?
Jb: Fs= m.w^2.r
= m (2phi/T)^2 r
= 2 (2phi/3)^2 5
= 40phi^2/9
5. the metal uranium has a density of 19g/cm pangkat 3 ...what is the mass of a block of uranium with a volume of 21,5 cm pangkat 3...
massanya adalah = 21,5 x 19 g = 408,5 gramm=ro×v
=19×21,5
=408,5 g
=0,4085 kg
6. a kitten and a basket has a mass of 3 kg . A hamster and a similar basket has a mass of 1.4kg . the mass of the kitten is 5 times the mass of the hamster .a. what is the mass of the hamster ? , b. what is the mass of the kitten ?
kitten = x ,hamster = y and baskest = z
x+z = 3 kg
y+z = 1,4 kg
z = x- y = 3 kg - 1,4 kg = 1,6 kg
x+y = 4,4 kg - 1,6 kg = 2, 8 kg
x = 5y
5y +y = 2,8 kg
6y = 2,8 kg
y = 2,8 kg /6
y = 0,47 kg
x = 5y
= 5 * 0,47 kg
= 2,35 kg
a. mass off hamster = 0,47 kg
b. mas off kitten = 2,35 kg
bonus...mass of basket = 1,6 kg
thank's
7. A 5g bullet moving at 100 m/s collides a wooden target, initially at rest. The mass of wooden target is 1kg. If after the collision the bullet is embed in the wooden block, what is the final speed of the wooden block?
This is innelastic collision. so we can use formula:
m1.v1+m2v2=(m1+m2)vf
5x100+1kgx0=(5+1000)vf
500+0=1005Vf
Vf=500/1005=0.49 m/s
8. A bullet with mass 10 gram is fired and hits a block which mass is 1.49 kg. The block is haning freely on a piece of rope of length with 0.2 m. If the acceleration due to the earth gravity is 10m/s² and the rope is displaced by 60 cm measured from its initial position/vertical position, the velocity of the bullet when fired is ... m/s
Hk Kekekalan Energi
(m+M).g.h = 1/2.(m+M).v'²
v' = √2gh
v' = √(2. 10. 0,6)
v' = 2√3 m/s
Hk Kekekalan Momentum
m.v + M.V = (m+M).v'
0,01. v + 1,49. 0 = (0,01+1,49). 2√3
0,01. v = 1,5. 2√3
v = 300√3 m/s
9. 3. A block of mass m/ = 4.0 kg is put on top of a block of mass m2 = 5.0 kg. To cause the top block to slip on the bottom one while the bottom one is held fixed, a horizontal force of at least 12 N must be applied to the top block. The blocks assembly is now placed on a horizontal, frictionless table, as shown in FIGURE 1. Find the magnitudes of a.the maximum horizontal force that can be applied to the lower block so that the blocks will move together b.the resulting acceleration of the blocks.
The maximum horizontal force that can be applied to the lower block is 5 N.The resulting acceleration of the blocks are 21,1 m/s².
Penjelasan dengan langkah-langkah:
Diketahui:
Massa 1 = 4 kg
Berat 1 = 40 N
Massa 2 = 5 kg
Berat 2 = 50 N
F1 = 12 N
Ditanya:
Gaya pada blok paling bawah (F2)?Percepatan (a)?Jawab:
∑Fy1 = 0
N1 - W cos θ = 0
12 - 120 cos θ = 0
12 = 120 c0s θ
cos θ = 0,1
∑Fx1 = m1 x a
120 - T = 4a....(1)
∑Fy2 = 0
N2 - w cos θ = 0
N2 = w cos θ
N2 = 50 (0,1) = 5 N
∑Fx2 = m2 x a
50 sin θ + T = 5a
50 x 1 + T = 5a
50 + T = 5a..........(2)
120 - T = 4a
50 + T = 5a
___________ +
190 = 9a
a = 21,1 m/s²
from that calculation, we know that:
The maximum horizontal force that can be applied to the lower block is 5 N.The resulting acceleration of the blocks are 21,1 m/s².Pelajari lebih lanjut
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10. a block of ice which has 20 kg of mass is receiving 67 kJ of heat. The number of ice melts is... (the melting point of ice is 335 kJ/kg)
Q = m.L
67 = m.335
m = 67:335
m = 0,2 kg
11. A block of monel alloy consist of 70% nickel and 30% copper.if it contains 88.2 g of nickel determine the mass of copper on the block ?
semoga jawabannya bener
12. A block of mass 500 g is pulled from rest on a horizontal frictionless bench by a steady force F and travels 8 m in 2 s. Find a the acceleration, b the value of F.
Jawaban:
F = m × a
d = vi × t + ½ × a × t²
Variabel yang Diberikan
m = 5 kg
vi = 0 m/s
d = 8 m
t = 2 s
8 = 0 m/s × 2s + ½ × a × 2s²
a = 4 m/s²
F = 5 kg × 4 m/s
F = 2 N
13. A kitten and a basket has a mass of 3 kg. A hanster and a similar basket has a mass of 1.4 kg. The mass of the kitten is 5 times the mass of the hamster. (a) what is the mass of the hamster? (b) what is the mass of the kitten?
hamster = x
kitten =y
basket=z
y=5x
x + z = 1,4
y+ z = 3. (+)
x-y = -1,6
x-5x=-1,6
6x = 1,6. x =0,267
y = 5x=5×0,267=1,335
14. Find A is 5kg heavier than object B is and the mass of object C is twice the mass of object A . If the total mass of three object is 255kg.Find the mass of Object C
A + B + C = 255 kgs
( B + 5 ) + B + 2 ( B + 5 ) = 55
4B + 15 = 255
4B = 255 - 15
4 B = 240
B = 60
C = 2( B + 5 )
C = 130
15. The mass of an Encyclopaedia is 1.05 kg. The mass of the encyclopaediais thrice the mass of a storybook.The mass of a dictionary book is 0.72 kgmore than the storybook. What is the mass of the dictionary bookuse working
Jawaban:
Massa sebuah Ensiklopedia adalah 1,05 kg. Massa ensiklopedia adalah tiga kali massa buku cerita. Massa buku kamus adalah 0,72 kg lebih dari buku cerita. Berapa massa buku kamus?
Massa ensiklopedia = 1.05 kg
Massa buku cerita = ⅓ massa buku ensiklopedia
cara — ⅓ x 1,05 = 0,35 kg
Massa kamus = massa buku cerita + 0,72 kg
cara — 0,35 + 0,72 = 1,07 kg
semoga membantu
jadikan jawaban terbaik ya..
16. the mass of a watermelon is 7/1 kg. the mass of a apples is 2/5 kg less than the mass of the watermelona. what is the mass of the applesb.what is the total mass of the apples and watermelon
Diketahui:
Berat semangka = 7/1 kg
Berat apel = 2/5 kg kurang dari semangka
Maka:
a. Berat apel = 7/1 - 2/5
= 35/5 - 2/5
= 33/5 = 6 3/5
b. Berat apel dan semangka = 7/1 + 6 3/5
= 35/5 + 33/5
= 68/5 = 13 3/5
Maaf klo salah
Semoga membantu
Jadikan jawaban terbaik ya...
17. The mass of a box with 2 marbles is 4.3 gram. The mass of each marbles is 1,3 gram. What is the mass of
Jawab:
the mass of a box is 1,7 gram.
Penjelasan dengan langkah-langkah:
18. a soldier jumps a platform of 2m to the ground. the mass of the soldier is 50kg. what is the impulse of the soldier when he hits the ground?
dikt= m= 50 kg
h= 2 m
ditanya . impuls ..?
impuls= mgh
= 50 10 2
= 1000
19. The mass of a dictionary is 1.28 kg. The mass of the dictionary is twice the mass of a storybook. The mass of an encyclopaedia is 1.4 kg more than storybook. What is the mass of the encyclopaedia?
Jawaban:
2.04 kg
Penjelasan dengan langkah-langkah:
Jika berat sebuah kamus 2 kali berat buku cerita, maka berat buku cerita adalah setengah dari berat kamus. Sehingga berat ensiklopedia adalah
1.4 kg + (1.28 ÷ 2) kg
= 1.4 kg + 0.64kg
= 2.04 kg
20. 23.A watermelon has a mass of 12.78 kg. Its mass is thrice the mass of a papaya. Find thetotal mass of the two fruits.
Jawaban:
mtk atau b inggris sih:)
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