A building is drawn with a height of 20 cm. The scale of the image of the building is 1 : 105. The actual height of the building is ... m.
1. A building is drawn with a height of 20 cm. The scale of the image of the building is 1 : 105. The actual height of the building is ... m.
Jawab:
Penjelasan dengan langkah-langkah:
height = 20 cm
scale 1 : 105
actual height = 20 x 105 = 2100 cm = 21 m
2. a ball with a mass of 2 kg is dropped from the top of a building and strikes the ground at a velocity of 10 m/s what is the heigt of the building from which the ball is dropped?
Materi : Kinematika Gerak Lurus
Sub materi : Gerak Jatuh Bebas
Mapel : Fisika
Kelas : X SMA (KTSP)
Keyword : GJB
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Diketahui :
m = 2 kg
v = 10 m/s
Ditanya :
h = ?
Penyelesaian :
Gerak jatuh bebas merupakan gerak benda dengan kecepatan awal benda Vo = 0 ,bisa dikatakan benda jatuh secara spontan.
Analisis soal :
A ball with a mass m kg dropped from the building which the height h meter. When the ball strikes, the velocity is 10m/s. The problem is what is the height of the building where the ball was dropped from?
Perhitungan :
v = √2gh
v² = 2gh
(10)² = 2(10)h
100 = 20h
h = 100/20
h = 5 m
So, the height of the building where the ball was dropped from is 5 m
-vin
3. A building is drawn to a scale of 1: 400. In the drawing (map), the height of the building is 3 cm. What is the actual height of the building in metres?
Actual height = 3 : 1/400=3×400= 1200cm =12m
Then, the actual height of the building is 12 m
4. Peter is standing at a point on level around 120 m away from the foot x of building a this angle of elevator of the top of building a is 28 this eye level is 15cm above the ground find the height of building
Jawaban:
height of building is 65.3 meter
Penjelasan dengan langkah-langkah:
Trigonometry
as attached
note : Peter's eye level must be 150 cm
5. a sepak takraw that is kicked from a height of two meters follows a path that is?
Jawaban:
sebuah sepak takraw yang ditendang dari ketinggian dua meter mengikuti jalan setapak itu?
6. A ball with a mass of 200g is placed on a compressed spring. The spring is then released and the ball bounces up. The compressed spring has 5 3 of elastic potential energy. : (a) Calculate the speed of the ball immediately when the ball bounces up. (b) What is the height that can be reached by the ball from the position it was released? [gravitational acceleration = 10ms ³]soal A nya saja please
Jawaban:
Gk tau
Penjelasan:
Gk bisa bahasa inggris :v
7. a sepak takraw that is kicked from a height of two meters?
Jawaban:
sebuah sepak takraw yang ditendang dari ketinggian dua meter?
8. A ball is thrown vertically upwards and reaches its maximum height 2.0 s later a. What is the initial velocity of the ball? b. What is the maximum height that the ball reaches?
Given : Time taken to reach the maximum height t=2 s
a=−g=−10m/s ^2
The initial velocity of the ball can be calculated by,
Using v=u+at
∴ 0=u−10×2 ⟹u=20 m/s
Using S = ut + 1/2at^2
S = 20.2 + 1/2 (-10)(2)^2
S = 40 + (-20)
S = 20m (the maximum height)
9. A ball A is thrown vertically upward from the top of a 30-m-high building with an initial velocity of 5 m/s. At the same instant another ball B is thrown upward from the ground with an initial velocity of 20 m/s. Determine the height from the ground and the time at which they pass.
Jawab:
Penjelasan dengan langkah-langkah:
10. 11. In the diagram, a flag is hung on a mast AB that is projected out of a building. AB = 5 m, AF = 12 m and ¿FAB = 113°. Find (a) the perpendicular distance from B to the vertical wall of the building, (b) the height of B above the ground.
SayaTataU47901467ya0
11. a warter reservoir at a height of 1.2 m is full of water. at the height of 90 cm from the water
90 cm = 0,09 m
12 m-0,09 m = 1,11 m
12. ADVANCED LEVEL 13. A flagpole of height 12.2 m is placed on top of a building of height h metres. From a point T on level ground, the angle of elevation of the base of the flagpole B is 26° and the angle of elevation of the top of the flagpole C is 35º. C 12.2 m B. hm 26°359 T
Jawaban:
makasi kak poinnya
Penjelasan dengan langkah-langkah:
setelah itu ia memiliki perhiasan emas di sea games Myanmar dan Thailand dan Malaysia ini adalah negara yang termasuk dalam kategori ini memiliki hati yg tulus dari dalam kategori
13. in the drawing the heigth of building is 10 cm. a building is drawn to a scale of 1 : 3.000. the actual height of building is?
Jawaban:
30000cm, or 300m, or 0.3 km
Penjelasan dengan langkah-langkah:
Scaled length × Scale = Actual length
10cm × 3000 = 30000cm
14. Physics IGCSE 0625/21/M/J/18 A ball of mass 1.2 kg is deopped from a height of 30 m. As it falls, 25% of its initial gravitational potential energy is transferred to thermal energy. What is the kinetic energy of the ball just before it hits the ground?
Jawaban:
Energi potensial (Ep)
Ep = mgh
= 1,2×10×30
= 12×30
= 360 J
Karena ada energi yang hilang (thermal energy), maka tidak ada konservasi energi
E thermal = 25% Ep
= 1/4 Ep
= 1/4×360
= 90 J
Ep = E thermal + Ek
360 = 90 + Ek
Ek = 270 J
Jawaban:
the kinetic energy of the ball just before it hits the ground is 270 Joule.
Penjelasan:
Conservation of mechanical energy states that the total energy of the system remains constant.
before the ball dropped, it has its potential energy defined by
Ep = m.g.h = (1.2)(10)(30) = 360 Joule
the kinetic energy is zero since the ball is at rest.
and when the ball hits the ground, the potential energy is zero while the kinetic energy becomes maximum.
since 25% of its initial potential energy is transferred to thermal energy, then the remaining potential energy is only 75%, it is 75% of 360 Joule = 270 Joule, and this is the only amount of energy that can be converted into kinetical energy then.
Therefore, the kinetic energy of the ball just before it hits the ground is 270 Joule.
Hopefully this is understandable and helpful.
Thank you
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15. A stone is dropped from the roof of a tall building of height 40m .what is the distance the stone fell through 1 second before it hits the ground ?Assume that the stone falls from rest and air resistance is neglected
Jawaban:
Distance the stone fell through 1 second before it hits the ground is 19,25 m.
Penjelasan:
Known =
h = high = 40 m
Assumed acceleration due to gravity (g) = 10 m/s²
Asked :
S = distance the stone fell through 1 second before it hits the ground = ....
Answer :
time for the stones fall to the ground
[tex]\boxed{t=\sqrt{\frac{2h}{g}}}[/tex]
[tex]t=\sqrt{\frac{2\times40}{10} }[/tex]
[tex]t=\sqrt{\frac{80}{10}}[/tex]
[tex]t=\sqrt{8}[/tex]
t = 2,83 s
distance the stone fell through 1 second before it hits the ground :
t = 2,83 - 1
t = 1,83
[tex]S=\frac{1}{2}gt^2[/tex]
[tex]S=\frac{1}{2}\times10\times1,83^2[/tex]
[tex]S=\frac{1}{2}\times10\times3,35[/tex]
S = 19,25 m
Learn more the materi in :
Materi Tentang Gerak vertikal sebuah batu yang dijatuhkan dari ketinggian h : https://brainly.co.id/tugas/24873060 #BelajarBersamaBrainly16. A building is 5 times as tall as a tree. The total height of the building and the tree together is 48 meters. How tall is the building?
Misalkan:
Tinggi gedung = g
Tinggi pohon = p
Dik :
g = 5p
g+p = 48 meter
Dit :
g?
Jawab :
• g + p = 48
5p + p = 48
6p = 48
p = 48/6
p = 8 meter
• g + p = 48
g + 8 = 48
g = 48-8
g = 40 meter
Jadi, tinggi gedung tersebut adalah 40 meter
17. 2. A rubber ball is dropped onto the floor from a height of ℎ metres. The time taken for it to stop bouncing is t seconds. This is given by the formula, where is a number that measures the ‘bounciness’ of the rubber ball. When dropped from a height of 1.25 m, it bounces for 2.5 s. a. Find the value of e b. For how long would the rubber ball bounce if it was dropped from a height of 1.8 m? c. The same rubber ball is dropped again, and this time it bounces for 3.5 s. find the height that it was dropped from.
a. [tex]t=(\frac{1+e}{1-e})\sqrt{\frac{h}{5}}\\2,5=(\frac{1+e}{1-e})\sqrt{\frac{1,25}{5}}\\2,5=(\frac{1+e}{1-e})\cdot0,5\\\frac{2,5}{0,5}=\frac{1+e}{1-e}\\5-5e=1+e\\6e=4\\e=\frac{4}{6}\\[/tex]
b. & c. just substitution the variable
Good luck
18. You drop a ball from a height of 2.0 m, and it bounces back to a height of 1.6 m. (a) What fraction of its initial energy is lost during the bounce? (b) What is the ball’s speed just before and just after the bounce? (c) Where did the energy go?
Jawaban sudah saya tulis di atas.
19. A ball is thrown vertically upwards and reaches its maximum height 2.0 s later a. What is the initial velocity of the ball? b. What is the maximum height that the ball reaches?
Jawaban:
a. 20m/s
b.20m
Penjelasan:
Given : Time taken to reach the maximum height t=2 s
a=−g=−10m/s ^2
The initial velocity of the ball can be calculated by,
Using v=u+at
∴ 0=u−10×2 ⟹u=20 m/s
Using S = ut + 1/2at^2
S = 20.2 + 1/2 (-10)(2)^2
S = 40 + (-20)
S = 20m (the maximum height)
20. tolong jawab ya pelajaran SD 1. A scale picture of a building is made to a scale 5 cm representing 15 m. If the height of the building on the picture is 8 cm, find the actual height of the building.2. A company makes a miniature motorbike to a scale of 1:24. If the length and height of the miniature motorbike is 8 cm and 5 cm successively, what is the actual length and height of the motorbike ?pelajaran math
Jawaban:
Skala = 5 cm : 15 m
= 5 cm : 1500 cm
= 1 : 300
Tinggi sebenarnya = tinggi gambar : skala
= 8 cm / 1:300
= 8 cm/1 x 300
= 2400 cm
= 24 m
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