Force F Is Given In Terms Of Time T

a spring is given a force of 80 N and its length gwors by 2 cm. If the given force is 100 N, the growth in length is

Daftar Isi

1. a spring is given a force of 80 N and its length gwors by 2 cm. If the given force is 100 N, the growth in length is

80/2=100/x
80x=200
x=2,5 cm

2. the Temple is in force of the

the temple is in force of the =

kuil ini di paksa

3. Given quadratic function f(x)=-[(x+6p)^2-5]+q has a maximum point T(-3n,15n^2).Express q in terms of p

[tex]
\text{Perhatikan bahwa}\\
\begin{aligned}
f(x)&=\left((x+6p)^2-5\right)+q\\
&=x^2+12px+36p^2-5+q\\
\text{Karena titik maksimum }& T(-3n,15n^2)\\
\text{Berarti diperoleh}\\
x&=-\frac{12p}{2\cdot1}\\
-3n&=-6p\\
n&=2p\\
\text{kemudian}\\
y&=f(x)\\
&=f(-6p)\\
15n^2&=(-6p)^2+12p(-6p)+36p^2-5+q\\
15n^2&=36p^2-72p^2+36p^2-5+q\\
15(2p)&=-5+q\\
30p+5&=q\\
\therefore q&=30p+5
\end{aligned}
[/tex]

4. produced Iron cube is... A pupil pushed the wagon with his two hands in a force of 90 N. If the area of a palm is 150 cm2, then the pressure given by the pupil is... Force

Jawaban:

heheh3jieoejjebebbeb3rhhdhfbbebehdhehehebebebevebvevevebeveveve geggeevge

Penjelasan:

bbvb'dbebbebeehh gue di belakang barisan tapi kok bisa sih tapi kalo gue mau tidur jam set alarm jam yang paling sabar aja nih anak satu sama siapa sih itu teh botol aqua blue and Black I'm sorry for the rest in the world

5. The momentum of a body is changed by a force acting on it for a period of time.Which action increases the change in momentum?

Jawaban:

Jawaban:

Manakah dari berikut ini yang merupakan kondisi yang diperlukan untuk momentum total suatu sistem untuk dilestarikan?

6. Express cos 3α in terms of cos α and tan 3α in terms of tan α

cos3x = cos (2x+ x)
=cos2x*cosx - sin2x*sinx
=(2*cos^2 (x) - 1) *cosx - 2sinx*cosx*sinx { since cos2x = 2cos^2 (X) -1 , sin2x = 2*sinx*cosx }
=2 cos^3 (x) - cos x - 2 cosx *sin^2 (x)
= 2 cos^3 (x) - cos x (1 + 2 sin^2 (x) )
= 2 cos^3 (x) - cos x (1 + 2 ( 1 - cos^2 (x) ))
= 2 cos^3 (x) - cos x ( 1+ 2 - 2*cos^2(x) )
=2 cos^3 (x) - cos x (3 -2*cos^2(x) )
=2 cos^3 (x) - 3cos x + 2*cos^3(x)
=4 cos^3 (x) - 3cos x

tan3x=tan(2x+x)
   =tan2x+tanx / 1-tan2x*tanx
   =2 tanx/1-t 2 x +tanx /1-2tanx*tanx/1-tan 2 x
   =2tanx+tanx-tan 3 x/tan 2 x-2tan 2 x
=3tanx-tan 3 x/1-3tan 2 x

Question:

The displacement x in metre of a particle of mass m kg moving in one dimension under the action of a force is related to the time t in second by the equation x= (t-3)². The work done by the force (in joules) in first six seconds is

Answer:

The work done is 18 m ( in Joules )

Explaination:

Giventhat

The displacement x in metre of a particle of mass m kgThe particle is moving in one dimension under the action of a force is related to the time t in secondsThe force is given by the equation x= (t-3)²

ToFind:

The work done by the force is first 6 seconds

RequiredSolution:

Let's find out the velocity of the particle differentiating

[tex]{ \leadsto \: { \boxed{ \pink{ \bf{Velocity = \frac{dx}{dt} }}}}}[/tex]

Calculating velocity :

[tex] : \implies \sf \: Velocity = \dfrac{dx}{dt} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ : \implies \sf \: Velocity = \frac{d}{dt} (t - 3) {}^{2} [/tex]

Usingformula:

[tex] \leadsto \: { \pink{ \boxed{ \bf{ \frac{d}{dx} ( {x}^{n}) = nx {}^{(n - 1)} }}}}[/tex]

[tex]: \implies \sf \: Velocity = \frac{d}{dt} (t - 3) {}^{2} \\ \\ : \implies \sf \: Velocity =2(t - 3) \: \: \: \: \\ \\ \\ : \implies \sf \: Velocity =2t - 6 \: \: \: \: \: \: \: \: [/tex]

CalculatingAcceleration:

[tex]: \implies \sf Acceleration = \dfrac{dv}{dt} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ : \implies \sf Acceleration = \frac{d}{dt} (2t - 6) \: \: \: \: \: \: \\ \\ : \implies \sf Acceleration = \frac{d(2t)}{dt} - \frac{d}{dt} (6) [/tex]

Usingformula:

[tex] \leadsto \: { \pink{ \boxed{ \bf{ \frac{d}{dx} ( {x}^{n}) = nx {}^{(n - 1)} }}}}[/tex]

[tex] : \implies \sf Acceleration = \frac{d(2t)}{dt} - \frac{d}{dt} (6) \\ \\ \\ : \implies \sf Acceleration = 2 \: \frac{d}{dt}( t )- 0 \: \: \: \: \: \\ \\ \\ : \implies \sf Acceleration = 2 - 0 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\: \implies \sf Acceleration = 2 \: m /s {}^{2} \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

UsingFormula:

[tex] \leadsto{ \pink{ \boxed{ \bf{Force = mass \times acceleration}}}}[/tex]

CalculatingForce:

[tex] \: : \implies \sf \:Force = mass \times acceleration \\ \\ \: : \implies \sf \:Force = m(2 ) \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: : \\ \\ : \implies \sf \:Force = 2m \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

CalculatingDisplacement:

[tex] \: : \implies \sf Displacement = (t - 3) {}^{2} \\ \\ \: : \implies \sf Displacement = (6 - 3) {}^{2} \\ \\ \: : \implies \sf Displacement = {3}^{2} \: \: \: \: \: \: \: \: \: \: \: \\ \\ \: : \implies \sf Displacement = 9 \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

UsingFormula:

[tex]{ \leadsto} \: { \pink{ \boxed{ \bf{ Work done = force \times displacemnet}}}}[/tex]

[tex] \: {: \implies }\sf \:Work done = force \times displacement \\ \\ \: {: \implies }\sf \:Work done =2m \times 9 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \: {: \implies }\sf \:Work done =18m \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

Henceforth:

The workdone by the particle is 18m ( in joules )

*Note:

If any confusion in the differentiation of the acceleration part of the question remember :

The differentiation of contestants is zero!!The differentiation of a variable woth power 1 will be one

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8. The circumference of a circle is πx.Find its area in terms of π and x.

Jawaban:

the working and the answer are attached.

semangat belajar

#first

9. Given that 3p = 5(1-r), express r in terms of p.

tengs in adpance

10. 2 9. The radius of a circle is 21 cm. Find the circumference of the circle in terms of t?

The circumference of the circle is 132 cm

Step by step

Circumference of the circle

= 2 × π × r

= 2 × 22/7 × 21

= 2 × 22 × 3

= 132 cm

Jawab:

Penjelasan dengan langkah-langkah:

radius(jari-jari)=21cm

cicumfence(keliling)=?

C=2xπxr

C=2x22/7x21

C=132cm

the cicumfence is 132cm

11. RESEARCH QUESTIONS: 1. What's the difference between ON, IN , AT in terms of TIME! (Perbedaan ON, IN ,AT dalam menunjukkan WAKTU) 2. What's the difference between ON, IN, AT in terms of PLACE! (Perbedaan ON, IN ,AT dalam menunjukkan TEMPAT) 3. Give some examples in sentence using ON,IN, AT in terms of TIME and PLACE! (Berikan contoh kalimat menggunakan ON, IN, AT, dalam menunjukkan WAKTU dan TEMPAT - masing-masing 1 kalimat)

Jawaban:

1.perbedaan ON,IN,AT

In dapat merujuk pada segala tempat yang tertutup. Jika ingin menunjukkan waktu, maka in memiliki makna dan penggunaan yang berbeda.Biasanya, on digunakan untuk menunjukkan tempat yang berada di permukaan. Di antara in dan on, penggunaan at akan menunjukkan sesuatu dengan lebih tepat.

Penjelasan:

12. Write 2 sentences by using "on" in terms of time. tolong kk..

Jawaban:

Sentences 1 :

- The cat is on the table

Sentences 2 :

- Your watch is on your desk

Penjelasan:

#Semoga Bermanfaat

#Jadikan Jawaban Tercerdas

#Semangat Belajar

13. . In a game of tug-of-war, both sides aren’t moving because each team have the same equal strength. What type of force is this? (10 Points) Balanced force Normal force Unbalanced force Spring Force

Jawaban: r u kelly from 6c

14. 3. Identify the descendants of the following quantities in terms of dimensions:a. Largeb. Volumec. Speedd. Force

Jawaban:

b.volume

semoga membantu

15. The total number of n terms inan arithmetic sequenceof X1, X2, X3..... Xn is 1.458. If the average of nterms is 6. What is n?

Jawab:

Penjelasan dengan langkah-langkah:

16. the figure is made up of 4 identical quadrants. leave your answer in terms of phi

Penjelasan dengan langkah-langkah:

The 4 identical quadrants will make a circle with radius of 8 and a diameter of 16 so we can solve the problem using the area of the circle

[tex] = \pi \times {r}^{2} \\ = \pi \times {8}^{2} \\ = \pi \times 64 \\ = 64\pi[/tex]

[tex]{\red{\fcolorbox{blue}{black}{\boxed{\bold{\blue{by }}}\boxed{\mathfrak{}\green{ pushrank21}}}}}[/tex]

17. two chargers q1 q2 in r distance have a repulsive force of f if the distance of both the charger is made into 0,5 r, the repulsive force is?

if the distance of both the charger is made into 0,5 r, the repulsive force is 4f

18. the component of this force in the horizontal direction is....

Jawaban:

b. 30 N

Penjelasan:

19. ....is the unit of force

Jawaban:

Newton is the unit of force

20. what is spring constant,if it is given force of 400n,and increace of 4cm length ....N/m

Jawaban:

F=400 N

4 cm = 0,04 m

[tex] \frac{400 \: n}{0.04} = 10.000 \: n \: per \: m[/tex]

Wawasan Genius