A particle P is moving in a horizontal circle about O. It moves at constant speed V. Which statement is true?
1. A particle P is moving in a horizontal circle about O. It moves at constant speed V. Which statement is true?
Jawaban:
There are several statements that could be true regarding a particle P moving in a horizontal circle about point O at constant speed V, but some possibilities include:
The centripetal acceleration of the particle P is given by a = V^2 / r, where r is the radius of the circle.
The direction of the centripetal force acting on the particle P is towards point O.
The particle P has a velocity vector that is tangential to the circle at every point along its path.
The angular velocity of the particle P, which is the rate at which it sweeps out angle as it moves around the circle, is given by ω = V / r.
Without additional information, it is not possible to determine which of these statements, or others, might be true.
Penjelasan:
2. A particle moves to the right along the x-axis. After t second, the particle position at X1 = 3 meters and after moving 4 seconds, the particle position at x2 = 12 meters. What is the average speed of the moving particles?
Jawaban:
3 m/s
Penjelasan:
S=12
t=4
v=S/t
v= 12/4
v=3 m/s
3. a vehicle moving with a uniform acceleration of 2m/s2 has a velocity of 4m/s at a certain time what will the velocity be in 1s later
acc, a = 2 m/s2
Kec. awal, Vo = 4 m/s
t = 1s
Vt = a . t + Vo
Vt = 2 . 1 + 4
Vt = 2 + 4
Vt = 6 m/s
4. calculate the kinetic energy possessed by: a. 3 kg objects move at 10m/s. b. the 2,500 kg car moving at a speed of 72km/h. c. 80g ball moving at 15m/s! i will make the best answer for anyone who answers this question. thank you
weight=massa=kg
velocity=kecepatan=m/s
kinetic energy=joule=(1/2)m.v²
a. (1/2).3.10²
=300/2
=150 joule
b.(1/2).2500.20² (72km/h=72000m/3600s=20m/s)
=2500.200
=50000 joule
c. (1/2).0,08.15² (80g=0,08kg)
=(1/2).0,08.225
=9 joule
5. The ball with mass of 0.1 kg moving at a speed of 20 m/s, the stick hits it with a force of 1.000 N in the opposite direction so that its speed becomes 40 m/s². what is the duration of stick touches the ball?
MOMENTUM
m = 0,1 kg
Vi = 20 m/s
Vt = - 40 m/s
F = - 1000 N
t = __?
I = ∆p
F t = m (Vt - Vo)
-1000 t = 0,1 (-40 - 20)
-1000 t = -6
t = 6/1000 s ← ans
The unit of velocity is m/s !
I = Δp
FΔt = m(v - v₀)
Δt = m(v - v₀) / F
= (0,1 kg)(-40 m/s - 20 m/s) / (-1000 N) = 6 x 10⁻³ s
6. Example: The velocity of a particle moving along the x axis varies in time according to the expression vx = (40 - 5t2) m/s, where t is in seconds. a. Find the average acceleration in the time interval t = 0 to t = 2.0 s b. Determine the acceleration at t = 2.0 s. Example: The velocity of a particle moving along the x axis varies in time according to the expression vx = (40 - 5t2) m / s, where t is in seconds. a. Find the average acceleration in the time interval t = 0 to t = 2.0 s b. Determine the acceleration at t = 2.0 s.
Jawaban:
a. - 10 m/s²
b. - 20 m/s²
Penjelasan:
Vx = (40 - 5t²)
a.
saat t₁ = 0 --> Vx₁ = 40 m/s
saat t₂ = 2 --> Vx₂ = 40 - 5. 4 = 20 m/s
Average acceleration
ar = ΔV/Δt = ( Vx₂ - Vx₁ ) / ( t₂ - t₁ )
ar = ( 20 - 40 )/( 2 - 0 )
ar = - 10 m/s² ( perlambatan )
b.
acceleration at t = 2.0 s.
a = dV/dt = - 10. t
a = - 10. 2 = - 20 m/s²
7. dika likes running at a slow reguler speed what is dika s hooby jawab;
the Hobby is running he likes running
8. Joanna drove a car at 40km/h. What is the speed in m/s?
Thank you for asking.
Dont forget to give a review and make this answer the brainlest answer
9. A 5g bullet moving at 100 m/s collides a wooden target, initially at rest. The mass of wooden target is 1kg. If after the collision the bullet is embed in the wooden block, what is the final speed of the wooden block?
This is innelastic collision. so we can use formula:
m1.v1+m2v2=(m1+m2)vf
5x100+1kgx0=(5+1000)vf
500+0=1005Vf
Vf=500/1005=0.49 m/s
10. ............ is an air moving across the surface of the planet or through the atmosphere at a speed fast enough to be noticed
adalah udara yang bergerak di seluruh permukaan planet atau melalui atmosfer pada kecepatan cukup cepat untuk diperhatikan
Hurricane or Tornado..
11. A particle travels 24.6 km in 30 minutes.Find the speed of the particlesin m/s
Jawab:
The speed is 49.2 km/hr.
Step-by-step explanation:
Given : A particle travels 24.6 km in 30 minutes.
To find : The speed of particle in km/h ?
Solution :
The distance is d=24.6 km
The time is t=30 minutes
Convert into hours :
1min = 1/60 hr
30 min = 0.5 hr
The speed formula is given by :
Speed : Distance/time
Speed : 24,6 / 0.5
Speed : 49,2 km/hr
#Learn more
https://brainly.in/question/11459948
Jawaban:
13,67 m/s
Penjelasan dengan langkah-langkah:
s = 24,6 km= 24600 m
t= 30 minutes= 1800 s
v=s/t
v=24600/1800
v=13,67 m/s
12. the speed of boat on calm water is 25 km per hour. If the boat is moving on a river whose water flows at speed of 5 km per hour. Find the speed that boat as : a. it is moving in yhe same direction as the water flowb. it is moving againist the direction of the water flow
Vkapal = 25 m/s
Vsungai = 5 m/s
a. Searah arus
Vkapal + Vsungai
= 25 m/s + 5m/s
= 30 m/s
b. Berlawanan arus
Vkapal - Varus
= 25 m/s - 5 m/s
= 20 m/s
nangkep soalnya begini, maaf kalau salah
13. A particle travels 28.5 km in 30 minutes. Find the speed of the particle in km/h
Jawab:
57 km/h
Penjelasan dengan langkah-langkah:
from the question, we know that:
D = 28,5 km
T = 30 minutes = 0,5 hour
Because the formula is Speed = [tex]\frac{distance}{time}[/tex]
so, Speed = [tex]\frac{28,5}{0,5}[/tex] = 57 km/h
Hope you find it helpful! Feel free to ask if there's something you don't understand from my explanation :)
14. A car covers 20 km in 30 minutes. It can be ascertained that the car is moving at a speed ...
Jawaban:
40 Km/Hour
Penjelasan:
The car covers 20 KM in 30 Minutes. That's mean 40 KM in 1 hour.
20 Km × 2 = 40 Km
so the car is moving at speed 40 Km per hour
15. A car is moving at 72 km/h=............m/s and it is declerated by 2 m/s in 10 s.Find it's speed in km/h.Write the way please
Jawaban:
648km/h
Penjelasan:
v=72 km/h=20m/s
a=2m/s
t=10s
vt=vot-at
vt=20x10-2x10
=200-20
=180m/s
vt=180x(10⁻³x3600)
=18x36=648km/h
16. energi mekanik , kinetik , potensial At her highest point,a girl on a swing is 2m from ground.While at her lowest point is 1m from the ground.Find maximum speed!
EM1=EM2; di posisi 1 atau tertinggi hanya punya energi potensial, pd posisi 2
punya ep dan ek
mgh=mgh+1/2 mv^2; m bs dicoret.
nanti akan ketemu v = 2√5 m/s
17. If an object has a mass of 8 kg moving at a speed of 10 m/s. the kinetic energy ( the object is… J A.400 B.800 C.80 D.40 Dengan cara ya
Jawaban:
400 J
Penjelasan:
The formula for kinetic energy:
Ek = [tex]\frac{1}{2}[/tex]mv²Ek = Kinetic Energy
m = mass
v = velocity
So, if the mass of the object is 8 kg, and it's moving at 10 m/s, then:
Ek = [tex]\frac{1}{2}[/tex] . 8kg . (10m/s)² = [tex]\frac{1}{2}[/tex] . 8kg . 100 m²/s² = 400 kgm²/s² = 400 JHence, the kinetic energy of the object is 400 J
18. The displacement(in metres) of a particle moving along x-axis is given by x=18t+5t^2.Calculate: i)instantaneous velocity at t=2s ii)instantaneous acceleration.
Given =
x = 18t + 5t²
Asked =
1.) Instantaneous Velocity at t = 2s
2.) Instantaneous Acceleration.
Answer =
1.) Instantaneous Velocity at t = 2s
[tex]\displaystyle v(t) = \frac{dx}{dt}\\\\v(t) = \frac{d}{dt}(18t+5t^2)\\\\v(t) = 18 + 10t[/tex]
so, when the t = 2s , the velocity will be
[tex]\displaystyle v(2) = 18 +10.2 \\v(2) = 18 + 20 \\v(2)= 38 \text{ m/s}[/tex]
2.) Instantaneous Acceleration
[tex]\displaystyle a = \frac{dv}{dt}\\\\a = \frac{d}{dt}(18+10t)\\\\a = 10 \text{ m/s}^2[/tex]
19. A particle travels 24.6 km in 30 minutes. Find the speed of particle in km/h
Jawaban:
49,2km/h
Penjelasan dengan langkah-langkah:
s = 24,6km
t = 30minutes or 0,5hours
v=s/t
v=24,6/0,5
v=49,2km/h
20. The displacement x of a point moving in a straight line is given by; The instantaneous velocity of the particle at t = 4 second will be:
KINEMATIKA
▶ GLBB
x = 3t⁴ + 3t³ - 5t² - 2t - 5
v = dx / dt
v = 12t³ + 9t² - 5t - 2
instantaneous velocity of the particle at t = 4 second will be :
v = 12(4)³ + 9(4)² - 5(4) - 2
v = 890 m/s ✔
0 Komentar