A Long Straight Wire Ab Carries A Current Of 4a

A wire 1 m long carries a current of 10 A. If the wire is placed in a 0.01 T magnetic field whose direction is at an angle of 60° to the direction of the current, the magnetic force experienced by the wire is...tolong jawab yaa makasihh

Daftar Isi

1. A wire 1 m long carries a current of 10 A. If the wire is placed in a 0.01 T magnetic field whose direction is at an angle of 60° to the direction of the current, the magnetic force experienced by the wire is...tolong jawab yaa makasihh

Jawaban:

Penjelasan:

F = B x i x l x Sin θ

F = 0,01 x 10 x 1 x Sin 60°

F = 0,1 x 0,5[tex]\sqrt{3}[/tex]

F = 0,05[tex]\sqrt{3}[/tex] N

2. A copper wire of cross-sectional area 2.0 mm2 carries a current of 10a. how many electrons pass through a given cross-section of the wire in one second ?

A copper wire of cross-sectional area 2.0 mm2 carries a current of 10a. how many electrons pass through a given cross-section of the wire in one second?

Sebuah kawat tembaga memiliki area potongan melintang 2.0 mm2 membawa arus 10a. Berapa jumlah elektron yang lewat melalui potongan melintang kabel tersebut dalam satu detik?

Jumlah elektron yang lewat melalui cross-section kabel tersebut adalah 6.25 x 10¹⁹ elektron/detik

Pembahasan:

Pertanyaan ini sedikit menjebak karena menyebut area potongan melintang yang dapat diabaikan.

Apa itu ampere?

Satu Ampere sama dengan satu Coulomb per detik

(1 A = 1 C).

Jadi,

10A = 10 Coulumb/detik

Apa itu coulomb?

Satu Coulomb (C) sama dengan kira-kira 6.241 x 10¹⁸ muatan dasar,

Atau 1 C = 6.241 x 10¹⁸ x Muatan Dasar

(Dimana Muatan Dasar memiliki konstan = 1.6 x 10⁻¹⁹ C)

= 6.241 x 10¹⁸ x 1.60217662 x 10⁻¹⁹ C

Jika,

1 C = 6.241 x 10¹⁸ elektron/detik

10 C = (10 C x 6.241 x 10¹⁸elektron/detik) / 1 C

= 6.241 x 10¹⁸ elektron/detik

Sekarang, muatan dasar selalu memiliki konstan 1.6 x 10⁻¹⁹ C, yang berarti anda akan mendapatkan 6.25 x 10¹⁸ elektron dalam satu Coulomb.

Jadi, jawabannya adalah:

10C x (6.25 x 10¹⁸ elektron/detik)/1 C = 6.25 x 10¹⁸elektron/detik.

Pelajari lebih lanjut:

Penjelasan tentang Arus Listrik https://brainly.co.id/tugas/8039693

Penjelasan tentang Tegangan listrik, Arus listrik, Hambatan listrik https://brainly.co.id/tugas/24426162

#BelajarBersamaBrainly #SPJ4

3. A straight wire carrying a current of 2A is placed in a 0.5 T magnetic field perpendicular to the current. If the Lorentz force acting on the wire is 2N, then the length of the wire is..tolong jawab yaa makasihh

Given :

I = 2 Amphere

B = 0,5 Tesla

F = 20 Newton

Asked : The Length of Wire ?
Answer :

[tex]\displaystyle F = B\times I \times L\\\\20 = 0,5 \times 2 \times L\\\\20 = 1 \times L\\\\20 = L[/tex]

So, The length of wire is 20 Meters

4. The weight of a piece of wire is directly proportional to its length. A piece of wire is 25 cm long and has a weight of 6 grams. What is the weight of another piece of the same wire which is 30 cm long.

step-by-step explanation :

According to the question

25 cm piece of wire has weight of 6 grams

So, 1 cm of wire will has a weight of 0.24 grams

( as 25cm weight = 6grams,

1cm = 6/25 grams = 0.24 grams)

As 1 cm = 0.24 grams so,

30 cm = 0.24 x 30 grams

= 7.2 grams

5. Agung has a 5 meter long wire (kawat). the wire is used to make a cube frame with a length of 35 cm. the rest of wire is

[tex]the \: length \: of \: a \: cube \: frame \\ 12 \: edges \times side \: length \\ 12 \times 35 \: cm \\ 420 \: cm \\ \\ the \: rest \: of \: wire \\ 500 \: cm - 420 \: cm \\ 80 \: cm[/tex]

6. Mynah had a piece of wire, k cm long. She cut off 7 cm of it and bent the remaining wire into an equilateral triangle. Each side of the equilateral triangle measured 13 cm. How long was the piece of wire?

Jawaban:

long piece the wire

= 7 + (13×3)

= 7 + 39 = 46 cm

K = 46

7. a long aluminum wire of diameter 3 mm is extruded at a temperature of 370°c. the wire is subjected to cross air flow at 30°c at a velocity of 6 m/s. determine the rate of heat transfer from the wire to the air per meter length when it is first exposed to the air.

answer:

Explanation:

Given:

Diameter of aluminum wire, D = 3mm

Temperature of aluminum wire, T_{s}=280^{o}CT

=280

Temperature of air, T_{\infinity}=20^{o}CT

\infinity

=20

Velocity of air flow V=5.5m/sV=5.5m/s

The film temperature is determined as:

\begin{gathered}T_{f}=\frac{T_{s}-T_{\infinity}}{2}\\\\=\frac{280-20}{2}\\\\=150^{o}C\end{gathered}

−T

\infinity

280−20

=150

from the table, properties of air at 1 atm pressure

At T_{f}=150^{o}CT

=150

Thermal conductivity, K = 0.03443 W/m^oCK=0.03443W/m

C ; kinematic viscosity v=2.860 \times 10^{-5} m^2/sv=2.860×10

−5

/s ; Prandtl number Pr=0.70275Pr=0.70275

The reynolds number for the flow is determined as:

\begin{gathered}Re=\frac{VD}{v}\\\\=\frac{5.5 \times(3\times10^{-3})}{2.86\times10^{-5}}\\\\=576.92\end{gathered}

Re=

2.86×10

−5

5.5×(3×10

−3

)

=576.92

sice the obtained reynolds number is less than 2\times10^52×10

, the flow is said to be laminar.

The nusselt number is determined from the relation given by:

Nu_{cyl}= 0.3 + \frac{0.62Re^{0.5}Pr^{\frac{1}{3}}}{[1+(\frac{0.4}{Pr})^{\frac{2}{3}}]^{\frac{1}{4}}}[1+(\frac{Re}{282000})^{\frac{5}{8}}]^{\frac{4}{5}}Nu

cyl

=0.3+

[1+(

0.4

)

]

0.62Re

0.5

[1+(

282000

)

]

\begin{gathered}Nu_{cyl}= 0.3 + \frac{0.62(576.92)^{0.5}(0.70275)^{\frac{1}{3}}}{[1+(\frac{0.4}{(0.70275)})^{\frac{2}{3}}]^{\frac{1}{4}}}[1+(\frac{576.92}{282000})^{\frac{5}{8}}]^{\frac{4}{5}}\\\\=12.11\end{gathered}

cyl

=0.3+

[1+(

(0.70275)

0.4

)

]

0.62(576.92)

0.5

(0.70275)

[1+(

282000

576.92

)

]

=12.11

The covective heat transfer coefficient is given by:

Nu_{cyl}=\frac{hD}{k}Nu

cyl

Rewrite and solve for hh

\begin{gathered}h=\frac{Nu_{cyl}\timesk}{D}\\\\=\frac{12.11\times0.03443}{3\times10^{-3}}\\\\=138.98 W/m^{2}.K\end{gathered}

cyl

\timesk

3×10

−3

12.11×0.03443

=138.98W/m

The rate of heat transfer from the wire to the air per meter length is determined from the equation is given by:

\begin{gathered}Q=hA_{s}(T_{s}-T{\infin})\\\\=h\times(\pi\timesDL)\times(T_{s}-T{\infinity})\\\\=138.92\times(\pi\times3\times10^{-3}\times1)\times(280-20)\\\\=340.42W/m\end{gathered}

Q=hA

−T∞)

=h×(π\timesDL)×(T

−T\infinity)

=138.92×(π×3×10

−3

×1)×(280−20)

=340.42W/m

The rate of heat transfer from the wire to the air per meter length is Q=340.42W/mQ=340.42W/m

Penjelasan:

8. length of wire is 20 cm long. It is bent at right angles to form the two A straight shorter sides of a right angled triangle. If the triangle's area is 30 cm find the length of the hypotenuse and the triangle's perimeter

Kawat membentuk sisi alas dan tinggi segitiga siku-siku.
misalkan:
alas = a
tinggi = t
Dengan demikian:
a + t = 20 cm
a = 20 - t

L = 1/2 a t
30 = 1/2 . (20 - t).t
60 = 20t - t²
t² - 20t + 60 = 0

t = (20 +/- √[ (-20)² - 4.1.60) ]/2.1
= (20 +/- √(400 - 240) ]/2
= (20 +/- √160)/2
= (20 +/- 4√10)/2
= 10 +/- 2√10

t = (10 + 2√10) cm
a = 20 - (10 + 2√10)
   = (10 - 2√10) cm

manentukan sisi miring (r) kita gunakan dalil phytagoras

r² = a² + t²
   = (10 - 2√10)² + (10 + 2√10)²
   = 100 - 40√2 + 40 + 100 + 40√2 + 40
   = 280
r = √280
= 2√70 cm

Keliling segitga:

K = a + t + r
   = 10 - 2√10 + 10 + 2√10 + 2√70
   = (20 + 2√70) cm

9. characteristric of hair a. wavy-blonde-pointed b. curly-pointed-straight c. long-blonde-flat d. curly-straight-wavy plis jawab

Penjelasan:

d. curly-wavy-straight

10. Wich wire allows a stronger current to pass through the short wire or the long wire

Long wire have bigger resistance which means less current to go to, shorter wire have smaller resistance. Remember the ohms law I = V/R.
Bigger R means lesser current.

11. arti dari aloop of wire between the poles of a magnet

English : A loop of wire between the poles of a magnet.

Bahasa : Lingkaran kawat di antara kutub magnet.

Jawaban:

pertanyaan:

arti dari aloop of wire between the poles of a magnet

Penjelasan:

Jawab:

arti dari "aloop of wire between the poles of a magnet" adalah = lingkaran kawat di antara kutub magnet

terima kasih semoga membantu maaf klo salah:3

#dirumahaja

#ayobelajar

12. John cuts a coil of wire into two pieces in the ratio of 5 : 1. The length of the coil of wire is 180 cm. How long is the long wire?

150 cm

Penjelasan dengan langkah-langkah:

the length of the long wire is

5/(1+5) x 180 cm = 5/6 x 180 cm

= 150 cm

13. 4. A student is provided with a 3.0 m long wire with a current of 0.15 A flowing through it. What is the strength of the magnetic field at the centre of the wire if the wire is bent into a circular coil of one turn ?

Jawaban sudah saya tulis, jadikan brainliest ya.

14. mr wong cuts a coil of wire into two pieces in the ratio 5:1 the leghth of the coil of wire is 180 cm.how long is the shorter piece of wire

ratio = 5 : 1
sum ratio = 5+1 = 6
Long = 180 cm
shorter piece = 1/6* 180 cm
=180 cm / 6
= 30 cm

good luck , follow yeah ,thank

15. 18. She ... (carry) her bag with a straight-down arm.a. carriedb. carryedC. carriesd. carriyed

a. carried

terimakasih sama sama

jadikan jawaban terbaik bila membantu

Jawaban:

a,carried

Penjelasan:

artinya dibawa, maaf ya kalau salah saya ga terlalu bisa bhasa inggris

16. Please Answer Correctly 1. If a 1.5 m length of resistance wire has a resistance of 1.9 Ω and the wire has a diameter of 0.9 mm, calculate the resistivity of the wire. 2. The length of a piece of wire is 4 m and the resistance is 1.6 Ω. If the electrical resistance of the wire is 8 x 10-7 Ωm, what is the cross-sectional area of the wire? 3. A 2m long piece of wire has a cross-section area of 0.15 mm2. What is the resistance of the wire if its resistivity is 2x10-8 Ωm? 4. A 2m long wire with a cross-sectional area of 1 mm2 has a resistance of 16 Ω. What is the resistance of the wire if the cross-sectional area is 2 mm2? 5. If the resistance of a wire is 16 Ω, the length of the wire is 4 m. What is the resistance of the wire if it is 1 m long? 6. The length of a wire is 1m. If the wire is now cut to 0.5 m, the resistance of the wire becomes .... (same/half times larger / twice larger) 7. If the 1.25 m length of resistance wire has a resistance of 3 Ω and the wire has a diameter of 0.5 m. The resistivity of the wire is...

Jawaban:

Tolong Jawab Dengan Benar

1. Jika kawat hambatan sepanjang 1,5 m memiliki hambatan 1,9 dan kawat memiliki diameter 0,9 mm, hitunglah hambatan kawat tersebut.

2. Panjang seutas kawat adalah 4 m dan hambatannya 1,6 . Jika hambatan listrik kawat adalah 8 x 10-7 m, berapa luas penampang kawat tersebut?

3. Sepotong kawat sepanjang 2m memiliki luas penampang 0,15 mm2. Berapakah hambatan kawat jika resistivitasnya 2x10-8 m?

4. Sebuah kawat sepanjang 2m dengan luas penampang 1 mm2 memiliki hambatan 16 . Berapakah hambatan kawat jika luas penampangnya 2 mm2?

5. Jika hambatan sebuah kawat adalah 16 , panjang kawat tersebut adalah 4 m. Berapakah hambatan kawat jika panjangnya 1 m?

6. Panjang seutas kawat adalah 1m. Jika kawat sekarang dipotong menjadi 0,5 m, hambatan kawat

menjadi .... (sama/setengah kali lebih besar / dua kali lebih besar)

7. Jika panjang kawat hambatan 1,25 m memiliki hambatan 3 dan kawat memiliki diameter 0,5 m. Resistivitas kawat tersebut adalah...

Penjelasan:

ini arti nya doang yaヾ(＾-＾)ノjawaban nya sendiri aja takut nya salah klo aku yg Jawabಥ‿ಥ makasih

17. One application of a magnetic force acting on a current-carrying wire in a magnetic field is the operating principle of most speakers in sound systems. Explain briefly how it works.

Magnet pada speaker berfungsi untuk mengubah energi listrik menjadi energi bunyi. Prinsipnya adalah magnet sebagai sumber medan magnet. Saat terdapat suara, speaker akan menghasilkan medan elektomagnet yang akan bertabrakan dengan medan magnet. Saat terjadi tabrakan inilah timbul getaran pada frekuensi tertentu yang dapat kita dengar.

Pembahasan

Magnet dapat dimanfaatkan untuk aktivitas sehari-hari. Salah satu pemanfaatan magnet adalah pada speaker atau pengeras suara. Pada speaker terdapat kombinasi antara magnet permanen dengan elektromagnetik. Adanya magnet membantu perangkat speaker dalam mengubah energi listrik menjadi energi bunyi.

Komponen elektomagnetik pada speaker memiliki kumparan yang biasa disebut voice coil.Voice coil ini berfungsi untuk membangkitkan medan magnet sehingga dapat menggerakkan cone speaker. Saat terdapat sinyal listrik yang melewati voice coil, akan terjadi perubahan pada arah medan magnet. Perubahan gerak ini menimbulkan gerakan tarikan dan tolakan dengan magnet permanen. Gerakan tarikan dan tolakan inilah yang menggerakkan cone speaker sehingga menghasilkan suara yang dapat kita dengar.

Pelajari lebih lanjut

Materi tentang manfaat magnet https://brainly.co.id/tugas/6298776, https://brainly.co.id/tugas/19692239, https://brainly.co.id/tugas/45988154

#BelajarBersamaBrainly

18. ahmad made a pyramid of wire with a square base with a side length of 8 cm and an upright edges of 10 cm.the length of wire needed is

Jawaban:

ahmad membuat sebuah piramida dari kawat dengan alas persegi dengan panjang sisi 8 cm dan rusuk tegak 10 cm. panjang kawat yang dibutuhkan adalah

19. FIGURE 1 below shows a circular loop L1 of radius 7 cm carries a 12 A current and another one loop L2 of radius 1.6 cm, having 30 turns and carrying a 3A current is placed at the centre of loop L1. What will be the resultant magnetic field at point P if the two current flow in the opposite direction?

A circular loop L₁ with a radius of 7 cm carries a current of 12 A and another circular loop L₂ with a radius of 1.6 cm, has 30 turns and a current of 3A is placed at the center of the circle L₁. The resultant magnetic field at point P if two currents flow in opposite directions is equal to [tex]2,305\pi \times 10^{-3}~T[/tex] or [tex]7,24 \times 10^{-3}~T[/tex] with the resultant inward.

Penjelasan dengan langkah-langkah:

Diketahui:

Kawat melingkar L₁ dengan radius r₁ = 7 cm dialiri arus listrik 12 A.Kawat melingkar L₂ dengan N = 30 lilitan dan radius r₂ = 1,6 cm dialiri arus listrik 3 A.Kedua kawat sepusat pada titik P.

Ditanya:

Berapakah resultan medan magnet di titik P jika kedua arus mengalir dalam arah yang berlawanan?

Proses:

Rumus induksi medan magnet kawat melingkar di pusat lingkaran adalah sebagai berikut.

[tex]\boxed{B=\frac{\mu_0 I N}{2a} }[/tex]

Keterangan:

B = medan magnet (T atau Wb/m²)I = kuat arus (A)N = banyak lilitana = radius (m)[tex]\mu_0 = 4\pi \times 10^{-7}[/tex]

Aturan tangan kanan pada kawat melingkar berarus.

Arah B = arah ibu jariArah I = arah putaran keempat jari tangan

Step-1: hitung medan magnet L₁

[tex]\boxed{B_1=\frac{(4\pi \times 10^{-7})(12)(1)}{2(7\times 10^{-2})} }[/tex]

[tex]B_1=3,43\pi \times 10^{-3}~T[/tex] dengan vektor B₁ berarah ke dalam.

Step-2: hitung medan magnet L₂

[tex]\boxed{B_2=\frac{(4\pi \times 10^{-7})(3)(30)}{2(1,6\times 10^{-2})} }[/tex]

[tex]B_2=1,125\pi \times 10^{-3}~T[/tex] dengan vektor B₂ berarah ke luar

Step-3: hitung resultan medan magnet di titik P

Misalnya acuan arah positif adalah ke dalam, maka [tex]\Sigma B = B_1 - B_2.[/tex]

[tex]\Sigma B = 3,43\pi \times 10^{-3}- 1,125\pi \times 10^{-3}[/tex]

[tex]\therefore \Sigma B = 2,305\pi \times 10^{-3}~T[/tex] atau [tex]\Sigma B = 7,24 \times 10^{-3}~T.[/tex]

Karena hasilnya positif, maka resultan medan magnetik berarah ke dalam.

Pelajari lebih lanjut

Pelajari materi tentang tentang cara memperbesar induksi magnetik pada solenoid melalui pranala https://brainly.co.id/tugas/8774859

#BelajarBersamaBrainly

20. a 2A current running through an infinitely long wire (up). 10 cm from the wire, there is a rectangular coil with a current 5A running counterclockwise. if the sides of the squares are 5 cm, what is the total force actin on the squares and to which direction?

jawabannya ada di foto ya..
semoga membantu :)

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