a ball with a mass of 2 kg is dropped from the top of a building and strikes the ground at a velocity of 10 m/s what is the heigt of the building from which the ball is dropped?
1. a ball with a mass of 2 kg is dropped from the top of a building and strikes the ground at a velocity of 10 m/s what is the heigt of the building from which the ball is dropped?
Materi : Kinematika Gerak Lurus
Sub materi : Gerak Jatuh Bebas
Mapel : Fisika
Kelas : X SMA (KTSP)
Keyword : GJB
ㅡㅡㅡㅡㅡㅡㅡㅡㅡㅡㅡㅡㅡㅡㅡㅡㅡㅡ
Diketahui :
m = 2 kg
v = 10 m/s
Ditanya :
h = ?
Penyelesaian :
Gerak jatuh bebas merupakan gerak benda dengan kecepatan awal benda Vo = 0 ,bisa dikatakan benda jatuh secara spontan.
Analisis soal :
A ball with a mass m kg dropped from the building which the height h meter. When the ball strikes, the velocity is 10m/s. The problem is what is the height of the building where the ball was dropped from?
Perhitungan :
v = √2gh
v² = 2gh
(10)² = 2(10)h
100 = 20h
h = 100/20
h = 5 m
So, the height of the building where the ball was dropped from is 5 m
-vin
2. A billiard ball rolling across a table to the right at 2.2 m/s makes a head-on elastic collision with an identical ball. The mass of a billiard ball is 36 g. If the first ball is initially moving to the left with a velocity of 1.1 m/s, what is the velocity of the second ball after the collision? Answer..... m/s
Penjelasan:
m1v1 = m2v2 - m1v1'
mv1 = mv2 - mv1'
v2 = v1 + v1'
= 2,2 + 1,1
= 3,3 m/s
bola 1 melaju dgn kec 2,2 setelah tumbukan benda 1 berbalik arah sehingga nilai momentum nya negatif
*ingat momentum juga merupakan vektor*.
3. A ball is initially at rest. The ball is then hit by a stick so that it is moving with velocity of 10 m/s. If the mass of the ball is 250 g, calculate the impuls applied to the ball!
Diketahui :
Vo = 0 m/s (bola diam)
Vt = 10 m/s
m = 0,25 kg
Ditanya :
Impuls?
Jawaban :
Impuls = ∆P
Impuls = m(Vt - Vo)
Impuls = 0,25 kg(10 m/s - 0 m/s)
Impuls = 0,25 kg * 10 m/s
Impuls = 2,5 kg*m/s
Correct me if i wrong
4. Tolong dijawab kak A ball is kicked at an angle of 37° with the ground. Determine the initial velocity of the ball so that it hits a target that is 32 m away at a height of 4 m.
Jawaban:
20 m/s
Penjelasan:
Sx = V0x . t
32 = V0 . cos 37° . t
t = 32 / V0 . cos 37°
t = 32 / V0 . 4/5
t = 40 / V0
V0y = V0 . sin 37°
V0y = 3/5 V0
Sy = V0y . t + 1/2 g . t²
4 = (3/5 V0) . (40 / V0) + 1/2 . (-10) . (40 / V0)²
4 = 24 - 5 (40 / V0)²
- 20 = - 5 (40 / V0)²
(40 / V0)² = -20/-5
(40 / V0)² = 4
40 / V0 = 4
40 = 2 V0
V0 = 20 m/s
5. 1. A-5 kg ball is dropped freely from a 24 m high. Find the greatest potential energy of the ball. (g = 10 N/kg) 2. A car moved at velocity of 30 m/s. Its mass was 2400 kg. what was the kinetic energy of the car by that time?
Answer:
1. 1200 J
2. 1080000 J
Explanation:
1.
P.E. = m . g . h
P.E. = 5 . 10 . 24
P.E. = 1200 J
2.
K.E. = 1/2 mv²
K.E. = 2400 . 30² / 2
K.E. = 2400 . 900 / 2
K.E. = 1080000 J
6. 10. Which of the following lists of physical quantitiesconsists only of vectors?a Acceleration, forse, and volumeb. Mass, velocity, and accelerationTime, mass, and velocityVelocity, acceleration, and force
Jawaban:
velocity, acceleration, force
Penjelasan:
mungkin pilihan gandanya sampe d ya
7. A small car with mass of 1000 kg is moving eastward with velocity of 30m/s and big car with mass of 2000 kg is moving southward with velocity of 20 m/s.The magnitude of momentum after colliding is..
Penjelasan:
dik : m1 = 1000 kg
v1 = 30m/s
m2 = 2000 kg
v2 = 20 m/s
dit: momentum atau p.... ?
jawab:
karna tidak ada diketahui koefisien dan cuma momentum setelah tabrakan maka menggunakan hukum kekekalan momentum sehingga persamaan seperti ini
p = p'
(m1 x v1) + (m2 x v2) = p'
p' = (1000 x 30) + (2000 x -20)
p' = 30.000 - 40.000
p' = -10.000
jadi besarnya momentum adalah -10.000 atau 10.000... mohon maaf kalau ada yang salah
8. A wagon with 15 kg of mass moves at velocity of 0,25 m/s toward a concreate wall. At the same time, a bullet 10 g mass is fired at velocity 1.000 m/s toward the wall. Calculate: a. The momentum of the wagon b. The momentum of the bullet
mass wagon = 15 kg
v wagon = 0,25 m/s
mass bullet = 0,01 kg
v bullet = 1000 m/s
a. P wagon = mass wagon * v wagon
= 15 kg * 0,25 m/s
= 3,75 kg*m/s
b. P bullet = mass bullet * v bullet
= 0,01 kg * 1000 m/s
= 10 kg*m/s
Correctmeifiwrong
9. A tennis ball is travelling at 50 m/s and has a kinetic energy of 75 J. Calculate the mass of the tennis ball.
velocity = V = 50 m/s
kinetic energy = Ek = 75 Joule
mass = m = .... ?
[tex]ek = \frac{1}{2} \times m\times {v}^{2} [/tex]
[tex]75 = \frac{1}{2} \times m \times {50}^{2} [/tex]
[tex]75 = \frac{1}{2} \times m \times 2500[/tex]
[tex]75 = 1250 \times m[/tex]
[tex]m = \frac{75}{1250} = 0.06 \: kg[/tex]
10. An object with mass x has a velocity of 30 m/s. Count the velocity of the object if the kinetic energy becoems 1/3 from original
Jawaban:
v = (10√3) m/s
Penjelasan:
Ek = 1/2 m v ²
= 1/2 . m . 30²
=( 450m )j
1/3 Ek = 1/3 . 450j
=( 150 m)j
Ek = 1/2 m v²
150m = 1/2 mv2
(150m)/(1/2m) = v²
v² = 300
v = √300
= √(100 . 3)
= (10√3) m/s
11. A car moves at the velocity of 20 m/s. The mass of the car is 1.5 ton. What is the kinetic energy of the car?
Energi Kinetik
Diketahui:
m = massa = 1.5 ton = 1.500 kg v = kecepatan = 20 m/s²Ditanya:
Ek = energi kinetik ? JawabanEk = ½ × m × v²
Ek = ½ × 1.500 × 20²
Ek = 750 × 400
Ek = 300.000 J ✔
atau
Ek = 300 kJ ✔
v = 20 m/s
m = 1,5 ton
m = (1,5 × 1.000) kg
m = 1.500 kg
Energi kinetik
Ek = 1/2 × m × v²
Ek = 1/2 × 1.500 × 20²
Ek = 1/2 × 1.500 × (20 × 20)
Ek = 1/2 × 1.500 × 400
Ek = 1/2 × 600.000
Ek = 600.000/2
Ek = 300.000 J
Ek = (300.000 ÷ 1.000) kJ
Ek = 300 kJ
12. An object of mass 1000 kg, initially having a velocity of 100 m /s, decelerates to a final velocity of 20 m/s. What is the change in kinetic energy of the object, in kJ?
ΔEk = 1/2.m.Vf² - 1/2.m.Vi²
ΔEk = 1/2.1000.20² - 1/2.1000.100²
ΔEk = 500.400 - 500.10000
ΔEk = 200.000 - 5.000.000
ΔEk = - 4.800.000 J
ΔEk = - 4.800 kJ
13. An empty box has a mass of 155 g, correct to the nearest grahi.A metal ball has a mass of 620 g, correct to the nearest gram.The metal ball is placed in the empty box and a reading of thetotal mass is taken. Find the smallest possible total mass of thetwo items
Jawaban:
haaa gimana mksdny gapaham,disuruh ngapain?
14. A ball travelling at 25 m/s and has a kinetic energy of 50 J. Calculate the mass of the ball !
velocity (v) = 25 m/s
KE = 50 J
mass (m) = ....?
KE = ½ × m × v²
50 = ½ × m × 25²
50 = ½ × m × 625
312.5m = 50
m = 50/312.5
m = 4/25
15. There were 3 similar big boxes of the same mass. There were another 4 similar small boxes of the same mass. The total mass of the big and small boxes was 90 kg. The moss of a big box was twice the mass of a small box. Find the total mass of a big box and a small box.
Jawaban:
27 kg
Penjelasan dengan langkah-langkah:
Semogaa menbantu yaaa
16. When a box contains 50 identical balls, it has a mass of 13.9 kg. The empty box has a mass of 400 g. Find the mass of each ball in kilograms.
mass of 50 balls = 13.9kg - 400g
= 13.9kg - 0,4kg
= 13.5kg
mass of each ball = 13.5kg/50
= 0.27kgKetika sebuah kotak berisi 50 bola yang sama, beratnya 13,9 kg. Kotak kosong itu beratnya 400 g. Temukan berat dari masing-masing bola dlam kg.
Dik:
Jumlah bola 50 bola
Berat total 13,9 kg
Berat kotak kosong 400 g = 0,4 kg
Berat bola keseluruhan = berat total - berat kotak kosong
= 13,9 kg - 0,4 kg = 13,5 kg
Berat masing-masing bola = berat bola keseluruhan : jumlah bola
= 13,5 kg : 50 bola = 0,27 kg/bola
Jadi berat masing-masing bola = 0,27 kg/bola
Translatenya:
Clue,
Numbers of balls = 50 balls
Total mass = 13,9 kg
Mass of empty box = 400 g = 0,4 kg
Total mass of balls = total mass - mass of empty box
= 13,9 kg - 0,4 kg
Mass of each ball = total mass of balls : numbers of balls
= 13,5 kg : 50 balls = 0,27 kg/balls
So the mass of each ball = 0,27 kg/balls
Semoga bisa membantu ＼(^o^)／
17. A tennis ball is thrown upward with initial velocity of 30 m/s, if g = 10 m/s2. Determine: a. height of the tennis ball at the first 2 seconds.b. velocity of the tennis ball at the first 2 seconds.c. time required by the tennis ball to reach the highest point.
Jawaban:
a. 40m
b. [tex]40m/s[/tex]
c. 3 second
Penjelasan:
KINEMATICS : PROJECTILE MOTION
Known :
Vo = [tex]30 m/s[/tex]
g = [tex]10 m/s^{2}[/tex]
a. height at t=2
[tex]h=Vot-\frac{1}{2}gt^{2}[/tex]
[tex]h= (30)(2) -\frac{1}{2}(10)(2)^{2}[/tex]
[tex]h=40m[/tex]
b. Vt at t=2
[tex]Vt= Vot-gt[/tex]
[tex]Vt = (30)(2) - (10)(2)[/tex]
[tex]Vt = 40 m/s[/tex]
c. time required to reach its highest point (t)
[tex]t= \frac{Vo}{g}[/tex]
[tex]t = 3s[/tex]
18. (1) The plastic cup has a mass of 2.5 g. What is the mass of one ball?
Jawaban:
This rock will not scratch glass.... Turn over
10 9 Safia wants to find the density of a small ball. (a) She measures the mass of a plastic cup containing ten identical balls.
Penjelasan:
Semoga membantu dan jadikan jawaban tercerdas
19. 5. (a) A copper ball has a mass of 1 kg. Calculate the radius of the ball, given that the density of copper is 8900 kg m^-3tolong ya kak makasih..
Jawaban:
3 x 10^-2 m
Penjelasan:
Massa = 1 kg
Massa Jenis = 8900 kg/m³
Massa Jenis = Massa / Volume
8900 kg/m³ = 1 kg/Volume
Volume = 1/8900 m³
V = 4/3 πr³
1/8900 = 4/3 x π x r³
r³ = 3/4π x 8900
r = 0,03 m = 3 x 10^-2 m
20. A sports shop has 6 light bowling balls and 6 heavy bowling balls. The mass of a heavy bowling ball is twice that of a light bowling ball. The total mass of the 12 bowling balls is 65.7 kg. Find the mass of a light bowling ball to the nearest kg.
Jawab:
The mass of a light bowling ball is 3,65kg.
Penjelasan dengan langkah-langkah:
So, 6 light bowling balls+6 heavy bowling balls=65,7kg
6lbb+6(2)lbb=65,7kg --> hbb=2lbb, so 6hbb=12hbb
6lbb+12lbb=65,7
18lbb=65,7
lbb=65,7/18
lbb=3,65kg
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