Look at the metal pendulum. The metal pendulum consists of a cone and a half sphere. If the radius of the half sphere is 10 cm and the slant height(apothem) of the cone is 20 cm, the surface area of the pendulum is....cm²
1. Look at the metal pendulum. The metal pendulum consists of a cone and a half sphere. If the radius of the half sphere is 10 cm and the slant height(apothem) of the cone is 20 cm, the surface area of the pendulum is....cm²
Lp pendulum = Lp 1/2 bola + Lp kerucut tanpa alas
L = 1/2 . 4 . phi . r² + phi. r . s
L = 2 . 3,14 . 10² + 3,14 . 10 . 20
L = 1256cm²
2. The metal pendulum consist of a cone and a half sphere if the radius of the half sphere is10 cm and the slant height (apothem) of the cone is 20 cm the surface area of the pendulum is
lpkerucut=phi×r(r+s)
=3.14×10(10+20)
=31.4×30
=942cmkubik
lp1/2bola=2phi×r kuadrat
=2×3.14×10×10
=624 cm kubik
surface area of pendulum =942+624
=1566cm kubik
3. find the volume of a sphere with radius 14mm
v= 4/3×π×r³ = 4/3×22/7×14×14×14 = 11498,6 mm³
4. look at the metal pedulum. the metal pendulum consists of a cone and a half sphere . if the radius of the half sphare is 10 cm and the slant height (apothem) of the cone is 20 cm , the surface area of the pendulum is....cm2
the surface area of pendulum =
[tex]2\pi. {r}^{2} + \pi.r.s[/tex]
= 2. 3,14. 100 + 3,14 . 10.20
= 628 + 628
= 1256 cm2
5. The price of a watch increases by 8% to $777.60. Find the original price of the watch.jangan ngasal + pake cara
Jawaban:
langkah 1:
100% - 8% = 92%
langkah 2:
777.60 - 92% =
777.60 - 92/100 = 685.6
langkah 3:
777.60 - 685.6 = 92
jadi untuk memastikan 8% dari 777.60 adalah 92
maka :
777.60 - 92 = 685.6
6. At 30℃ the volume of an aluminum sphere is 30 cm3. The coefficient of volume expansion is 72 x 10 -6℃. If the final volume is 30.5 cm3, what is the final temperature of the aluminum sphere? A.231,48 ℃ B.201,48 ℃ C.261,48 ℃ D.216,48 ℃
Jawaban:
C. 261,48 C
Penjelasan:
maaf kalo salah
Jawaban:
nomer 12 ap
C. 261.48°C
7. the surface area of a sphere is 462 cm persegi . find the volume! (π= 22/7)
lihat gambar ya kakak:)Dik : Luas permukaan bola = 462 cm²
π = 22/7
Dit : Volume bola ?
Jawab :
L permukaan bola = 4πr²
462 = 4.π.r²
462 = 4 (22/7) . r²
r² = (462 x 7) / (4 x 22)
r² = 3234 / 88
r² = 1617/44
r = 6.062
Volume bola = 4/3 πr³
= 4πr² . r/3
= 462 . 6.062/3
= 933,548 cm³
8. The density of steel is 7850 kgm Calculate themass of a steel sphere of radius 0.15 m. (Firstcalculate the volume of the sphere using theformula V = $rt and then use the density equation.)
Penjelasan:
[tex]V sphere = \frac{4}{3} \pi {r}^{3} \\ = \frac{4}{3} \times 3.14 \times {(0.15)}^{3} = 0.01413 \: {m}^{3} [/tex]
[tex]ρ = \frac{m}{V} \\ 7850= \frac{m}{0.01413} \\ m = 7850 \times 0.01413 \\ = 110.9205 \: kg[/tex]
9. The volume of a sphere with a radius 12 cm is … cm3 .
volume = 4/3 x 3,14 x 12 x 12 x 12
= 21703,68 : 3
= 7234,56
~ Les•Online ~
10. find the volume of a sphere with radius 4m
Penjelasan dengan langkah-langkah:
volume of sphere = 4/3 × phi × r³
4/3 × 3,14 × 4³ = 267,9048 m³
11. the acceleration of an electron in electric field of a positively charged sphere is inversely proportional to the square of the distance between the electron and the centre of the sphere. let an electron fall from rest at infinitely to the sphere. what is the electron velocity when it reaches the surface of the sphere
Jawaban:
percepatan elektron dalam medan listrik bola bermuatan positif berbanding terbalik dengan kuadrat jarak antara elektron dan pusat bola. biarkan sebuah elektron jatuh dari keadaan diam tak terhingga ke bola. berapa kecepatan elektron saat mencapai permukaan bola.
Penjelasan:
Jadijawabannya:29
12. Find the volume of a sphere with a radius 5.8 cm
Rumus volume bola
V = 4/3 x π x r³
Keterangan :
V = volume bola.
r = jari-jari bola.=5,8 cm
π = 22/7 atau 3,14
v=4/3×3,14×5,8³
v=27479,47cm³
13. A solid metal sphere of surface area 394,24 cm2 is melted down and recast as a solid circular cone of height 5.6 cm. find the base radius of the cone.
Jawaban:
the working and the answer are shown in the pic.
semangat belajar....
14. After the price increases by 20%, a tie is now sold for $24. What was the original price of tie
Jawaban:
$20
Penjelasan dengan langkah-langkah:
Setelah harga menaik 20%
Harga = 100% + 20% = 120%
120% x harga normal(A) = $24
6/5 x A = 24
A = 24 x 5/6
A = 20
Jadi, harga normal sebuah dasi adalah $20
15. fifty-four solid hemispheres each of diameter 2cm, are melted to form a single sphere. find the radius of the sphere.
arti indonesianya..Empat puluh empat belahan solid masing-masing berdiameter 2cm, dilebur untuk membentuk bola tunggal. temukan radius bola.
smga membantu
16. explain why rubbing one side of a metal sphere does not cause it to become charged
Answer:
Now for the iron rod as it is a conductor their atoms have electrons in motion as a result of this rubbing it with a cloth will not create any big difference in making it charged because of its stable higher number of electrons,they will never allow more electrons to move through them.
17. A metal has a density of 750 kg / m3. If the mass is 30 kg. Calculate the volume of the metal
Penjelasan:
HgvjbfvkfwfjudnjgbjhvbjutaadbkkJawaban:
0,04 m³
Penjelasan:
Diket :
Ρ= 750 kg / m3
m = 30 kg.
Dit :
v
Jawab:
p = m/v
750 = 30/v
750v = 30
v = 0,04 m³
Semoga membantu : )
18. What is the volume of a sphere with radius 3 cm
Jawaban:
113.04 cm³
Penjelasan dengan langkah-langkah:
[tex]volume = \frac{4}{3} \pi {r}^{3} [/tex]
V = (4/3) × 3.14 × 3³
= 113.04 cm³
19. What is the volume of sphere with radius 3 cm in cm3
Jawaban:
113.04 cm³
Penjelasan dengan langkah-langkah:
[tex]volume = \frac{4}{3} \pi {r}^{3} [/tex]
V = (4/3) × 3.14 × 3³
= 113.04 cm³
20. a cylinder and a cone of the same height 2r and the same base diameter 2r. A sphere has a diameter of 2r. Find the ratio of the volume of the cylinder to that of the cone and to that of the sphere
Jawab:
6:1:4
Penjelasan dengan langkah-langkah:
Volume of the cylinder = [tex]\pi r^{2}h=\pi r^{2}(2r)=2\pi r^{3}[/tex]
Volume of the cone = [tex]\frac{1}{3} \pi r^{2}h=\frac{1}{3} \pi r^{2}(2r)=\frac{2}{3} \pi r^{3}[/tex] and,
Volume of the sphere = [tex]\frac{4}{3} \pi r^{3}[/tex]
thus, the ratio of the volume of the cylinder to that of the cone and to that of the sphere are
Volume of the cylinder : Volume of the cone : Volume of the sphere
[tex]2\pi r^{3}:\frac{2}{3} \pi r^{3}:\frac{4}{3} \pi r^{3}\\=2:\frac{1}{3} : \frac{4}{3} \\=6:1:4 \\[/tex]
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