A Particle Moves Along A Circle Of Radius 20 Ï€

The circumference of circle is 248 a. circle radius b. area of the circle

Daftar Isi

1. The circumference of circle is 248 a. circle radius b. area of the circle

Diketahui:

The circumference of ⭕ = 248

Ditanya:

➊ The circle radius? ➋ Area of the circle?

Jawab:

➊ A circle radius

[tex]Circumference = \pi \times diameter \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ 248 = 3,14 \times diameter \\ diameter= \frac{248}{3,14} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ diameter = 78,98 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ diameter = 79 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ radius = 79 \div 2 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ radius = \boxed{39,5} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

So, the circle radius is [tex] \boxed{39,5} [/tex]

➋ Area of the circle

[tex]= \pi \times {r}^{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ = 3,14 \times {39,5}^{2} \: \: \: \: \: \: \: \\ = 3,14 \times 1.560,25 \\ = 4.899,185 \: \: \: \: \: \: \: \: \: \: \: \: \: \\ = \boxed{4.899,2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

So, area of the circle is [tex] \boxed{4.899,2} [/tex]

☻ stay healthy ☻

2. A circle has a radius of 10,5 meter. The circumference of the circle is

66 m

Penjelasan dengan langkah-langkah:

r = 10,5 m

d = 10,5 x 2 = 21 m

K = πd

= 22/7 x 21 m

= 66 m

3. a circle has a radius of 22 cm. the circumference of the circle is

Jawaban:

artinya

sebuah lingkaran memiliki jari-jari 22 cm. keliling lingkaran tersebut

Penjelasan:

maaf kalo salah

4. the area of a circle of radius 49 cm is

Penjelasan dengan langkah-langkah:

dik: r = 49 cm

dit: luas lingkaran

luas lingkaran = π × r × r

= 22/7 × 49 × 49

= 7.546 cm2

semoga membantu :)

5. Quizz EasyA circle has a radius of 7 cm. Then the circumference of the circle is ...Note:Good Luck Everyone

K = 2 × phi × r

K = 2 × 22/7 × 7

K = 2 × 22

K = 22 + 22

K = 44

Jadi, Keliling lingkaran tersebut adalah 44

✿ Penyelesaian ✿

K = 2 × Phi × r
K = 2 × 22/7 × 7
K = 2 × 22
K = 22 + 22
K = 44

✿ Kesimpulan ✿

Keliling Lingkaran Tersebut Adalah 44 cm

Semoga Membantu ツ !

6. A particle moves for 10 s with velocity 4 m/s and then moves with velocity 6 m/s for another 20 s and finally moves with velocity 8 m/s for next 30 s. What is the average velocity of the particle?

Jawaban:

average v= v1 + v2 + v3

= (10×4) + (20x6) + (8 x 30)

= 40 + 120 + 240

= 400 = 133.33 m/s

7. A circle has an area of M cm2 and a circumference of N cm.if m/n=20,then the radius of circle is cm

Sebuah lingkaran memiliki Arean dari M cm2 dan lingkar N cm. jika m / n = 20, maka jari-jari lingkaran adalah cm
itu artinya

8. A particle moves with a position vektor of r(t)=4t^i+(6t-2)j+3k.the vector of the particle at t=1second is

~Vektor Gaya~

Diketahui
r = 4t[tex]^{i}[/tex] + ( 6t - 2 ) + 3k
t = 1

Ditanya
Posisi vektor =__?

Jawab
karena t = 1 maka posisi vektor
r = 4[tex]^{2}[/tex] + ( 6t - 2 )j + 3k
r = 4. 1[tex]^{i}[/tex] + ( 6(1) - 2 )j + 3k
r = 4. 1[tex]^{i}[/tex] + 3j + 3k

9. Find the following. (Use t = 3,14)a The radius of the circle with a diameter of 125 cm.b The area of the circle with a radius of 10,5 cm.c The circumference of the circle with a diameter of 144 cm.PLS BANTU PLS

Jawaban:

A. 10,5 cm

B. 347.,28 cm²

C. 452,16 cm

Penjelasan dengan langkah-langkah:

Point A.

Diameter 125 cm,

[tex]d = 2r \\ 125 = 2r \\ r = \frac{125}{2} \\ = 62.5 \: cm[/tex]

Point B

r = 10.5 cm

[tex]a = \pi {r}^{2} \\ = 3.14 \times 10.5 \times 10.5 \\ = 347.28 \: {cm}^{2} [/tex]

Point C.

d = 144 cm,

[tex]c = \pi .d \\ = 3.14 \times 144 \\ = 452.16 \: cm[/tex]

10. A particle moves to the right along the x-axis. After t second, the particle position at X1 = 3 meters and after moving 4 seconds, the particle position at x2 = 12 meters. What is the average speed of the moving particles?

Jawaban:

3 m/s

Penjelasan:

S=12

t=4

v=S/t

v= 12/4

v=3 m/s

11. 1.The diameter of a circle is 20 m, so the radius is .. 2.The circumference of a circle with the diameter of 14 cm is .... 3.The circumference of a semi circle with the diameter of 14 cm is .... 4.The radius of a circle is 28 cm. The area of a quadrant is ...

Jawab:

1. 10 m

2. 44 cm

3. 36 cm

4. 154 cm²

Penjelasan dengan langkah-langkah:

1. Radius = half diameter = 20 /2 = 10 m

2. Circumference = 2 x 22/7 x 7 cm = 44 cm

3. Circumference = diameter + half circumference = 14 + 22/7 x 7 = 36 cm

4. Area quadrant = 1/4 x 22/7 x 14 x 14 = 154 cm²

12. The circumference of a circle that has a radius of 15 cm is... (3.14)

K=2πr
K=2*3,14*15
K=30*3,14
K=94.2

13. 2 9. The radius of a circle is 21 cm. Find the circumference of the circle in terms of t?

The circumference of the circle is 132 cm

Step by step

Circumference of the circle

= 2 × π × r

= 2 × 22/7 × 21

= 2 × 22 × 3

= 132 cm

Jawab:

Penjelasan dengan langkah-langkah:

radius(jari-jari)=21cm

cicumfence(keliling)=?

C=2xπxr

C=2x22/7x21

C=132cm

the cicumfence is 132cm

14. A planet of mass p moves in a circular orbit of radius r round a sun ....

moving in the sun

semoga bermanfaat

15. A circle has an area of 64rt cm? Work out the radius of the circle.

r = 8 cm

Penjelasan dengan langkah-langkah:

r² = L : π

= 64π : π

= 64

r = √64 = 8 cm

16. A circle with diameter of 210 has a radius of … *900420No Answer105.

Jawaban:

diameter= 210

radius= 1/2.diameter

radius=1/2.210

radius=105

Penjelasan dengan langkah-langkah:

semoga jelas

17. find the circumference of a circle with radius (a).30 cm (b).100cm

Jawab:

a. 188,5 cm

b. 628,3 cm

Penjelasan dengan langkah-langkah:

Circumference = 2 × π × radius

a. 2 × π × 30 cm = 188,5 cm

b. 2 × π × 100 cm = 628,3 cm

#BACKTOSCHOOL2020

18. A particle P is moving in a horizontal circle about O. It moves at constant speed V. Which statement is true?

Jawaban:

There are several statements that could be true regarding a particle P moving in a horizontal circle about point O at constant speed V, but some possibilities include:

The centripetal acceleration of the particle P is given by a = V^2 / r, where r is the radius of the circle.

The direction of the centripetal force acting on the particle P is towards point O.

The particle P has a velocity vector that is tangential to the circle at every point along its path.

The angular velocity of the particle P, which is the rate at which it sweeps out angle as it moves around the circle, is given by ω = V / r.

Without additional information, it is not possible to determine which of these statements, or others, might be true.

Penjelasan:

19. A circle has a radius of 56 cm. Determine the area of the circle!

r = 56

L = [tex]\pi[/tex]r²

L = 22/7 x 56 x 56

L = 9.856 cm²

Answer :

Given : -

A circle radius = 56cm

Find it : -

Determine the area circle!

Solution : -

L = 22/7 × 56 × 56

L = 22 × 8 × 56

L = 9.856cm²

-Ihopethishelps

20. A skater moves with 15 m/s in a circle of radius 30 m . The ice exert a central force of 450 N. What is the mass of the skater. (GAFSA)

Jawaban:

BANYAK BANGET MASALAH AKU BUNUH DIRI AJA AKU UDAH GK KUAT NAMA AKU SEPTIAN HAKIM MINTA MAAF JIKA ADA SALAH

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