At A Height H From The Surface Of Earth

An object has weight 2 N on the surface of the earth. What is its weight if it is brought to the height of 1 500 km from the surface of the earth? [Radius of the earth = 6 370 km, g= 9.81 N kg-']

Daftar Isi

1. An object has weight 2 N on the surface of the earth. What is its weight if it is brought to the height of 1 500 km from the surface of the earth? [Radius of the earth = 6 370 km, g= 9.81 N kg-']

Jawaban:

w = 1,310700617 N

Penjelasan:

Karena soal ini berada di brainly.co.id, maka saya akan menjawab soal ini menggunakan bahasa indonesia

Cara mengerjakan soal ini adalah dengan cara memahami konsep gravitasi, maka

//Pertama Kita cari dulu massa dari objek

w = m . g

m = w / g

m = 2 / 9,81

m = 0,20387 Kg

//Kita cari Percepatan gravitasi pada h = 1500 Km = 1500000 m

g = G . M / R²

g = 6,67 e-11 . 5,97 e24 / (6370000 + 1500000)²

g = 6,4291 m/s

//Kita cari w pada h = 1500 Km

w = m . g

w = 0,20387 . 6,4291

w = 1,310700617 N

Semua jawaban yang saya berikan adalah hasil dari pembulatan

Semoga membantu

2. If the gravitational acceleration at Earth’s surface g and the radius of the earth R, the gravitational acceleration at a point has a distance R from the surface of the earth is…. 1/2 g g 2 g 1/4 g 4 g

Penjelasan:

`°Gravitasi Newton°`

g1/g2 = (r2/r1)²

g/g2 = ((R + R)/R)²

g/g2 = (2R/R)²

g/g2 = 2R²/R²

g/g2 = 2/1

g2=1/2g(A)

~firmansyahmaulanailh~

3. the surface of the earth becomes..............when it turns away from the sun

Jawaban:

Dark

Penjelasan:

jangan lupa like Follow

the earth's surface becomes shadow when it is turned away from the sun

4. Please help me to solve this question The gravitational force of a satellite on the surface of the Earth of radius R is F. What is the gravitational force on the satellite when its height is R above the Earth?

Jawaban:Jawaban:

F/4

Penjelasan:

h = distance from earth core to satellite

h = R+R = 2R

Fb = gravitational force on the satellite when its height is R above the Earth

F = G m / R^2

Fb = GM m / (2R)2

Fb = GM m / 4R2

Fb = (GM m / R2) / 4

Fb = F/4

Semoga membantu.

5. find the surface area of a cylinder of radius 5cm and height 10cm

Jawaban:

=150πcm

Penjelalasan:

Given

The Radius of a solid cylinder (r)=5cm

Height (h)=10cm

Hence

Total surface area =2πrh+2πr

=2πr(h+r)

=2π×5(10+5)

=π×10×15

=150πcm

(don't forget to give thanks:)

6. every 45 metres height from the sea surface,the temperature decreased by 0,5C.if the temperature on the surface is 27C,what is the temperature on 3,600m height over the sea surface?

3600:45 l = 80
80x0.5 = 40
27-40 = ....

7. On a particular day, the height of the tide at East Coast Park was 0.8 m at dawnAt dusk the height of the tide increased by 40%. Find the height of the tide at duse

Jawab:

Hi, Oppung will answer your question.

Here it is.

The height of the tide at East Coast Park = 0.8 m at dawn

increased by 40% means:

[tex]40\% \times 0.8 \\= \frac{40}{100} \times 0.8\\=0.4 \times 0.8\\=0.32[/tex]

Therefore, the height of the tide at East Coast Park = 0.8 m + 0.32 = 1.12 m

at dusk.

8. a warter reservoir at a height of 1.2 m is full of water. at the height of 90 cm from the water

90 cm = 0,09 m
12 m-0,09 m = 1,11 m

9. The gravitational force of a satellite on the surface of the Earth of radius R is F. What is the gravitational force on the satellite when its height is R above the Earth?

Jawaban:

F/4

Penjelasan:

h = distance from earth core to satellite

h = R+R = 2R

Fb = gravitational force on the satellite when its height is R above the Earth

F = G m / R^2

Fb = GM m / (2R)2

Fb = GM m / 4R2

Fb = (GM m / R2) / 4

Fb = F/4

10. 15. circular cone has a height of 17 mm and a slantheight of 21 mm. Find(i) the volume(ii) the total surface area,of the cone.

15.kerucut bundar memiliki tinggi 17 cm dan tinggi miring 21 cm. temukan volume total luas permukaan kerucut.

jadikan yang terbaik☺️

11. 17. What is a geyser?a.The changing of temperature be-neath the surface of the earthb. From a huge tension of heated wa-ter that coming out from the earthcrackc.From the heated temperature inearth crack that absorbing waterd.From the temperature andabsorbed water that occurs onearth surfacee.The result of underground waterunder the combined conditions of high temperatures and increased pressure beneath the surface of the earth

Jawaban:

B.From a huge tension of heated wa-ter that coming out from the earth crack

Penjelasan:

A geyser is a kind of hot spring that gushes periodically, emitting hot water and steam into the air.

(Geiser adalah sejenis mata air panas yang menyembur secara periodik, mengeluarkan air panas dan uap air ke udara.)

12. find the surface area of a cylinder of radius 6cm and height 7cm

Penjelasan dengan langkah-langkah:

CIRCLE

r = 6 cm

h = 7 cm

S.a = 2πr(r + h)

S.a = 2 × 3,14 × 6 × (6 + 7)

S.a = 37,68 × 13

S.a = 489,84 cm² ✔

13. the rock formed on the surface of the earth at the conditions of temperature and low pressure is called

stones that form on the earth's surface under conditions of low temperature and pressure are called _sedimentary rocks_

14. An object in a space probe above the Earth weights 3.5N. The gravitational fieldstrength at the height of the space probe is 7.0 N/kg. The gravitational fieldstrength on the Earth's surface is 10 N/kg. What are the mass and the weight ofthe object on the Earth's surface?

Jawaban:

massa 2.0

weight 3.5

Penjelasan:

maaf kalo salah

15. 2. The distance between the satellite from the surface of the Earth is 35000 km. If theradius of the Earth is 6.38 x 106 m, what is the gravitational field of the satellite?

Jawaban:

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Class 11

>>Physics

>>Gravitation

>>Gravitational Potential Energy

>>As you have learnt in the text, a geosta

Question

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As you have learnt in the text, a geostationary satellite orbits the earth at a height of nearly 36,000 km from the surface of the earth. What is the potential due to earth's gravity at the site of this satellite ? (Take the potential energy at infinity to be zero). Mass of the earth = 6.0×10

kg, radius = 6400 km.

Medium

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Solution

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Mass of the Earth,M=6.0×10

Radius of the Earth, R=6400 km=6.4×10

Height of a geostationary satellite from the surface of the Earth, h=36000 km=3.6×10

Gravitational potential due to Earth's gravity at height h

V=−

R+h

=−

3.6×10

+0.64×10

6.67×10

−11

×6×10

=−9.4×10

J/kg

16. 17. What is a geyser?a. The changing of temperature be-neath the surface of the earthb. From a huge tension of heated wa- ter that coming out from the earth crackc. From the heated temperature in earth crack that absorbing waterd. From the temperature andabsorbed water that occurs onearth surfacee. The result of underground waterunder the combined conditions of high temperatures and increased pressure beneath the surface ofthe earth

Jawaban:

Penjelasan:

Geyser adalah hasil dari air bawah tanah dibawah kondisi suhu tinggi dan tekanan yang meningkat di bawah permukaan bumi.

17. Determine the gravitational force attractional between the earth ( m=5,98 X 10^24 kg) and a 66,7 kg satelite is flying on the earth surface at distance of 6.67 X 10^6 m from earth center

GRAVITATION

F = ___?
M = 5.98×10^24 kg
m = 66.7 kg
r = 6.67×10^6 m

F = G M m / r²
F = 6.67×10^−11× 5.98×10^24 × 66.7)/(6.67×10^6)^2
F = 598 N ✔️Dicari Fgravitasi

Fgravitasi = G.mbumi.msatelit/r²
G = 6,67x10^-11
Mbumi = 5,98x10^24
Msatelit = 66,7 kg
Maka
Fgravitasi = 6,67x10^-11 . 5,98x 10^24 . 66,7/ 6,67 x 10^6 . 6,67 x 10 ^6

Tinggal dicoret yah, jadinya
F gravitasi = 5,98x10^24. 10. 10^-23
F gravitasi = 598N

Semoga membantu:)

18. 13. Diagram shows a satellite at an altitude, h km from the surface of the Earth. Find the value of h.[G = 6.67 X 10-11 N m2 kg?, Mε = 5.97 x 1024 kg, R = 6370 km, g = 8.49 m s?).

Jawaban:

kakajajangajaggajajagagakajagaft

dojdnxodd

kerjain sendiri

19. What is the Surface Temperature of Planet Earth

Jawaban:

minimal:−89,2 °c

Average:15 °C

Maximum:56,7 °C

Penjelasan:

Earth is the third planet from the Sun which is the densest planet and the fifth largest of the eight planets in the Solar System. Earth is also the largest of the four terrestrial planets of the Solar System

Jawaban:

assalamualaikum hi brother and sister back again with gardian

________________________

Question :

1. What is the Surface Temperature of Planet Earth

________________________

Answer :

- 61°F

Average Temperature on Each Planet

The average temperatures of planets in our solar system are: Mercury - 800°F (430°C) during the day, -290°F (-180°C) at night. Venus - 880°F (471°C) Earth - 61°F (16°C)

________________________

pelajarin lebih lanjut :

1. https://solarsystem.branily.gov/resources/681/solar-system-temperatures/

_______________________

detail jawaban :

mepel : b. inggris

kelas : menengah atas

materi pembelajaran : sistem tata surya

bab : -

code kelas : 6 . 7 . 5

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20. A satellite moves in a circular orbit around Earth at a speed of 5000 m/s. Determine (a) the satellite’s altitude above the surface of Earth and (b) the period of the satellite’s orbit.

v = 5000 m/s
G = 6,67×10^-11
M = 5,98×10^24 kg
r = 6378×10^3 m

a. Circular orbit velocity follows the equation below :
v = square root GM/r+h
Where,
v ; circular orbit velocity
G ; universal gravitational constant
M ; Earth's mass
r ; Earth's radius
h ; height
h = GM/v^2-r
h = 9586399 m = 9586 km

b. Period of the satellite
T = square root 4pi^2(r+h)^3/GM
T = 5,57 hours

Wawasan Genius